How many pounds must a sand bag weigh to test if a safety net can absorb the proper amount of force?

Mathematics

1 answer:

Agata [3.3K]3 years ago

4 0

its 400lbs
hope i helped

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Question Help The mean finish time for a yearly amateur auto race was 185.64 minutes with a standard deviation of 0.314 minute.

Inga [223]

Answer:

Sam has the more convincing victory with a greater Zscore value

Step-by-step explanation:

Given that :

Year 1:

Mean finish time (m) = 185.64

Standard deviation (s) = 0.314

Sam's time (x1) = 185.29

Year 2:

Mean finish time (m) = 110.3

Standard deviation (s) = 0.129

Rita's time (x1) = 110.02

Zscore = (x - mean) / standard deviation

Sam's Zscore :

(185.29 - 185.64) / 0.314

= - 0.35 / 0.314

= −1.114649

= - 1.115

Rita's Zscore :

(110.02 - 110.3) / 0.129

= - 0.28 / 0.129

= −2.170542

= - 2.171

Sam has the more convincing victory with a greater Zscore value

5 0

2 years ago

Solve this equation: y-3x+15=10

Jlenok [28]

Answer:

10=10

Step-by-step explanation:

y-3x+15=10

y=3x-15+10

y=3x-5

subtitute y=3x-5 in the above equation:

3x-5-3x+15=10 (3x will be eliminated with -3x)

-5+15=10

10=10

(i hope this is the way you want the answer but at least I think it is correct)

3 0

3 years ago

Solve the initial value problem. dy/dt = 1 + 6/t , t > 0, y = 8 when t = 1

nordsb [41]

$\displaystyle\frac{dy}{dt} = 1 + \frac{6}{t}\ \Rightarrow\ dy = \left( 1 + \frac{6}{t}\right) dt\ \Rightarrow\int 1\, dy = \int \left( 1 + \frac{6}{t}\right) dt \ \Rightarrow \\ \\
y = t + 6\ln|t| + C. \text{ But $t\ \textgreater \ 0$ so }y = t + 6\ln t + C. \\ \\ 
y(1) = 8\ \Rightarrow\ 8 = 1 + 6 \ln 1 + C \ \Rightarrow\ C = 7 \text{ so } \\ \\
y(t) = t + 6\ln t + 7$