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Sidana [21]
2 years ago
11

What’s the area of a square the side is 7x-3

Mathematics
1 answer:
Gnoma [55]2 years ago
4 0

Area of a square = Side × Side

Side = 7x-3

Area of the square = (7x-3) × (7x-3)

= 7x(7x-3) -3(7x-3)

= 49x^2 -21x -21x +9

=49x^2 -42x +9

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Find the volume of the square pyramid shown
Daniel [21]
C is the correct answer
5 0
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Does anyone know the answer
lesya [120]
If the square translates to 7 units on the right and 6 units downwards, the following changes will be made:
 
Point S will have the coordinates of (3, -5).

Point R will have the coordinates of (-1, -5).

Point U will have the coordinates of (-1, -9).

Point  T will have the coordinates of (3, -9).

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5 0
3 years ago
Solve for x in the equation x squared + 2 x + 1 = 17.
Papessa [141]

Answer:

x = - 1 + \sqrt{17}\\and\\x = - 1 - \sqrt{17}\\

Step-by-step explanation:

given equation

x^2 +2x +1 = 17

subtracting 17 from both sides

x^2 +2x +1 = 17\\x^2 +2x +1 -17= 17-17\\x^2 +2x - 16 = 0\\

the solution for quadratic equation

ax^2 + bx + c = 0 is given by

x = x = -b + \sqrt{b^2 - 4ac} /2a \\\\and \ \\-b - \sqrt{b^2 - 4ac} /2a

________________________________

in our problem

a = 1

b = 2

c = -16

x =( -2 + \sqrt{2^2 - 4*1*-16}) /2*1 \\x =( -2 + \sqrt{4  + 64}) /2\\x =( -2 + \sqrt{68} )/2\\x = ( -2 + \sqrt{4*17} )/2\\x =  ( -2 + 2\sqrt{17} )/2\\x = - 1 + \sqrt{17}\\and\\\\x = - 1 - \sqrt{17}\\

thus value of x is

x = - 1 + \sqrt{17}\\and\\x = - 1 - \sqrt{17}\\

3 0
2 years ago
Help please asap thx
Lelechka [254]

Answer:

2 and a half, but it wants it as a mixed fraction which would be 5/2

Step-by-step explanation:

i hope this helped :)

7 0
3 years ago
Read 2 more answers
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