Question

Given the following equation: le="y = 3(x+8)^{2} + 6" alt="y = 3(x+8)^{2} + 6" align="absmiddle" class="latex-formula">
What would be the vertex (h,k)
Vertex = (_,_)

Answer 1

Answer: $h=-8\\k=6$

Step-by-step explanation:

By definition, we know that the quadratic equation in the vertex form is:

$y=a(x-h)^{2}+k$

Where (h, k) is the vertex.

We have thefollowing equation given in the problem:

$y=3(x+8)^{2}+6$

Therefore, you can conclude that the vertex is (-8,6).

Therefore the answer is:

$h=-8\\k=6$

Answer 2

Answer:

The vertex of given equation is (-8,6).

Step-by-step explanation:

We have given an equation in vertex form.

y  = 3(x+8)²+6

We have to find vertex of the given equation.

y  = a(x-h)²+k where (h,k) denotes vertex of the equation.

y  = 3(x-(-8))²+6

Comparing both equations, we have

h  = -8 and k  = 6

hence, the vertex of given equation is (-8,6).