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3 years ago

Which of the following graphs is described by the function given below?

Mathematics

1 answer:

dusya [7]3 years ago

6 0

Step-by-step explanation:

D. Graph D the answer is D

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Quadratic Equations and Functions - Part 2

exis [7]

Answer:

See below

Step-by-step explanation:

<u>Given function</u>

h(t) = 5 + 98t – 4.9t²

<u>Filling in the table using the function, substitute t for each line:</u>

<u>time | elevation</u>

The graph is attached

4 0

3 years ago

Read 2 more answers

Which variable will you choose to eliminate? How?

Inga [223]

Answer:

Variable elimination

8x+3y=-7
3y=-8x-7
y=-8/3x-7/3

Now plug it into y
7x-16/3x-14/3=-3
5/3x-14/3=-3
5/3x=5/3
x=1

4 0

3 years ago

jeremy puts on empty container under a leaking faucet. in the first hour 3/8 quart of water collects. in the second hour, 1/6 qu

QveST [7]

Answer:

13/24

Step-by-step explanation:

=3/8+1/6=9/24+4/24=(9+4)/24=13/24

7 0

4 years ago

Given the parent functions f(x) = log3 (5x − 5) and g(x) = log3 (x − 1), what is f(x) − g(x)?. . a. f(x) − g(x) = log3 (4x − 4).

grandymaker [24]

$f ( x ) = log _{3} ( 5 x - 5 ), g ( x ) =log _{3} ( x - 1 ); \\ f ( x ) - g ( x ) = log _{3}( 5 x - 5 ) - log _{3}( x - 1 ) = \\ log _{3} \frac{5(x-1)}{x-1} = log _{3} 5$
Answer: C ) f ( x ) - g ( x ) = log3 5

8 0

3 years ago

In a survey of 100 out-patients who reported at a hospital on a day, it was found that 70 complained of fever, 50 had stomach tr

cluponka [151]

Answer:

3 patients had all the three complaints

Step-by-step explanation:

Let U be the set of patients who reported at the hospital on that day

Let F be the set of patients who complained of fever

Let S be the set of patients who had stomach troubles

Let I be the set of injured patients

Then the given data can be written as:

n(U) = n(F∪S∪I) = 100
n(F) = 70
n(S) = 50
n(I) = 30
n(F∩S) + n(S∩I) + n(I∩F) - 3×n(F∩S∩I) = 44

n(F∩S∩I) = ?

Using the formula for the cardinal number of union of three sets:

n(F∪S∪I) = n(F) + n(S) + n(I) - n(F∩S) - n(S∩I) - n(I∩F) + n(F∩S∩I)

100 = 70 + 50 + 30 - (44 + 3×n(F∩S∩I)) + n(F∩S∩I)

100 = 150 - 44 - 2×n(F∩S∩I)

2×n(F∩S∩I) = 106 - 100 = 6

3 0

3 years ago