A bag contains 7 red marbles, 3 blue marbles, 1 green what is the prob. of choosing a marble not blue?

Ratling [72]

Percent mean parts out of 100 0.2%=0.2/100=0.02/10=0.002/1=0.002 'of' means multiply 'what number'=x 'is' means '=' so 0.2% of what number is 12 0.002 times x=12 divide both sides by 0.002 x=6000 the number is 6000

3 0

4 years ago

Read 2 more answers

There are 9 red, 5 yellow, and 7 green jellybeans in a jar. Without replacement what is the probability of choosing a green jell

Mrac [35]

Answer:

3/14 chance first draw

Step-by-step explanation:

There are 14 jellybeans in all, you won’t be replacing so the probability will change with each draw.

Probability the 1st draw is red = 3/14.

Probability the 2nd draw is red = (3–1)/(14–1) = 2/13.

Probability the 3rd draw is red = (2–1)/(13–1) = 1/12.

3/14 x 2/13 x 1/12 = 6/2184 = 1/364 is approximately 0.27%, pretty rare.

8 0

3 years ago

Members of the student concil are conducting a fundraiser by selling school calendars. After selling 80 calendars, they had a lo

Oksana_A [137]

Answer:

a) $y=8x-1000$

b) $profit=\$8$

c) They'd have lost $1000 if they had sold no calendars.

Step-by-step explanation:

a) The equation of the line in Slope-Intercept form is:

$y=mx+b$

Where "m" is the slope and "b" is the y-intercept.

In this case we know that "y" represents the profit of loss and "x" the number of calendars sold.

Then, according to the exercise, the line passes through these two points:

$(80,-360)$ and $(200,600)$

Then, we can find the slope of the line with the formula $m=\frac{y_2-y_1}{x_2-x_1}$

$m=\frac{-360-600}{80-200}=8$

Now, we can substitute the slope and one of those points into $y=mx+b$ and solve for "b":

$600=8(200)+b\\\\b=-1000$

Then, subtituting values, we get that the equation that describes the relation between the profit of loss and the number of calendars sold, is:

$y=8x-1000$

b) The slope of the line is the profit they made from selling each calendar

$profit=8$

c) The y-intercept is the amount they would have lost if they had sold no calendars:

$b=-1000$

They'd have lost $1000 if they had sold no calendars.

6 0

3 years ago

A textbook store sold a combined total of 477 sociology and math textbooks in a week. The number of sociology textbois sold was

denpristay [2]

Answer:

The correct answer is 218 math textbooks and 259 sociology textbooks.

Step-by-step explanation:

To solve this problem, we can make a system of equations. Let the number of sociology textbooks sold be represented by the variable "s" and the number of math textbooks sold be represented by the variable "m". Using these variables, we can make two equations:

s + m = 477

m + 41 = s

There are many ways to solve this system of equations. One approach we can take is substituting the value for s given by the second equation into the first equation. This is modeled below.

s + m = 477

(m + 41) + m = 477

Combining like terms on the left side of the equation yields:

2m + 41 = 477

Subtracting 41 from both sides of the equation gives us:

2m = 436

Finally, dividing both sides of the equation by 2 gives us:

m = 218

To solve for the number of sociology textbooks, we can substitute into either of our original equations.

m + 41 = s

(218) + 41 = s

s = 259

Therefore, your answer is m = 218 and s = 259, or 218 math textbooks and 259 sociology textbooks were sold.

Hope this helps!

6 0

3 years ago

Captain Ben has a ship, the H.M.S Crimson Lynx. The ship is five furlongs from the dread pirate Luis and his merciless band of t

grigory [225]

Answer:

We can see that this is dependent probability. We can find dependent probability of happening event A then event B by multiplying probability of event A by probability of event B given that event A already happened.

Step-by-step explanation:

In our case event A is pirate hitting captain's ship and event B is captain missing pirate's ship. We have been given that pirate shoots first so pirate's ship can't be hit before pirate shoots his cannons. So probability of hitting captain's ship is 1/3. We have been given that if Captain Ben's ship is already hit then Captain Ben will always miss. So the probability of Captain missing the dread pirate's ship given the pirate Luis hitting the Captain ship is 1. Now to find probability that pirate hits Captain, but Captain misses we will multiply our both probabilities.

8 0

4 years ago