Answer:
96x^3+24x^2-432x+270
Step-by-step explanation:
hope it helped
Answer and Step-by-step explanation:
C(x) be the statement "x has a cat"
D(x) be the statement "x has a dog"
F(x) be the statement "x has a ferret".
Universe = x = all students in your class.
a) A student in your class has a cat, a dog and a ferret
= ∃x(C(x) ∧ D(x) ∧ F(x))
b) All students in your class have a cat, a dog, or a ferret = ∀x(C(x) ∨ D(x) ∨ F(x))
c) Some students in your class has a cat and a ferret but not a dog = ∃x (C(x) ∧ F(x) ∧ ¬D(x))
d) No student in this class has a cat, a dog and a ferret ¬∃x (C(x) ∧ D(x) ∧ F(x))
e) For each of the three animals, cats, dogs and ferrets, there is as student in your class who has one of the three animals. (∃xC(x)) ∧ (∃xD(x)) ∧ (∃xF(x))
Answer : $18.75
Bethany is paid time-and-a-half for each hour she works above her normal 40 hours each week. Last week, Bethany worked 44 hours and her gross pay was $575.
Total hours worked = 44 hours
Normal 40 hours + 4 hours extra
Let x be the amount earned for 1 hour for regular 40 hours
1.5x be the amount earned for extra hours
40 (amount earned for normal hours ) + 4(amount for extra hours ) = gross pay
40x + 4(1.5x) = 575
40x + 6x = 575
46 x = 575
Now divide both sides by 46
x = 12.5
1.5x is the amount earned for extra hours
1.5 * 12.5 = 18.75
Bethany earn for each hour of overtime she worked is $18.75
60% is her score as a percentage
