This will be the sum of the probability that exactly 10 have the same suit plus the probability that 9 of 10 have the same suit.
With replacement first. Let's focus on a single suit, say hearts.
The probability of drawing on a heart on the first draw is 1/4. Since we're replacing, that's the probability of a heart for cards two through ten. So the probability of all hearts is .
Since there are four suits, the probability of drawing all the same suit is four times the above, .
The probability of drawing the first 9 hearts then a different suit for the 10th is .
The different suit may be any of the cards so we multiply this by 10 to get the probability of 9 of 10 hearts: .
We can have any suit, so we multiply this by a factor of 4, giving .
The probability we seek is the sum P(10 the same) + P(9 the same)
Answer: P(with replacement) = 0.012%
Now let's do it again without replacement.
P(Exactly 10 hearts). We have a 13/52 chance of picking a heart on the first card. Given we did, we have a 12/51 chance of picking a heart on the second card. So for all 10, we get
Let's write that as
Again the four suits gives us
For 9 of 10, the last fraction 4/43 becomes 39/43, then we multiply by 10 because any of the cards might not match and 4 to cover the suits.
So a total probability of
Answer: P(without replacement) = 0.00071%
A lot smaller.
I'd have to check this pretty hard to be sure it was right, which I haven't done.