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Slav-nsk [51]
3 years ago
14

Is this shape a polygon?

Mathematics
2 answers:
Allushta [10]3 years ago
8 0
No its not  polygons dont cross lines 

Varvara68 [4.7K]3 years ago
8 0
No, it crosses itself.
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2 years ago
A parabola has its vertex at (2, 1) and crosses the x-axis at (1,0) anu al l
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Answer:

A

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

Here (h, k) = (2, 1), thus

y = a(x - 2)² + 1

To find a substitute (1, 0) into the equation

0 = a(1 - 2)² + 1

0 = a + 1 ( subtract 1 from both sides )

a = - 1

Hence

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3 years ago
Find all integers $n$ for which $\frac{n^2+n+1}{n-1}$ is an integer.
Grace [21]
\dfrac{n^2+n+1}{n-1}=\dfrac{(n-1)^2+3(n-1)+3}{n-1}=n-2+\dfrac3{n-1}

The remainder term \dfrac3{n-1} will never vanish, and will always be rational as long as the denominator is not 1, 3, or -3.

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7 0
3 years ago
What is the equation of the line that passes through the points (15, 9) and (Negative 2, 9)? y =
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\bf (\stackrel{x_1}{15}~,~\stackrel{y_1}{9})\qquad (\stackrel{x_2}{-2}~,~\stackrel{y_2}{9}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{9}-\stackrel{y1}{9}}}{\underset{run} {\underset{x_2}{-2}-\underset{x_1}{15}}}\implies \cfrac{0}{-17}\implies 0 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{9}=\stackrel{m}{0}(x-\stackrel{x_1}{15})\implies y-9=0\implies y=9

3 0
3 years ago
Read 2 more answers
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