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PSYCHO15rus [73]
4 years ago
11

Question 1: On a coordinate plane, triangle ABC has vertices at A(10,5), B(10,15), and C(5,5). Triangle A'B'C' has vertices at A

' (30,12), B'(30,52), and C(10,12). Which transformation maps triangle ABC onto triangle A'B'C'? A. (x,y) --> (3x, 3y + 3) B. (x,y) --> (4x - 10, 4y - 8) C. (x,y) --> (4x + 10, 4y + 8) D. (x,y) -> (3x, 3y - 3) ​
Mathematics
1 answer:
Vilka [71]4 years ago
4 0

Answer:

B. (x,y) --> (4x - 10, 4y - 8)

Step-by-step explanation:

Transformation is the movement of a point from its initial location to a new location. Types of transformation are reflection, translation, dilation and rotation.

If a point X(x, y) is translated a units right and b units up, the new location is (x + a, y + b) also If a point X(x, y) is translated a units left and b units down, the new location is (x - a, y - b)

If a point X(x, y) is dilated by the factor k the new location is X'(kx, ky).

Triangle ABC has vertices at A(10,5), B(10,15), and C(5,5), If it is dilated by a factor of 4, the new location is A*(40, 20), B*(40, 60) and C*(20, 20). If then a translation of 10 units left and 8 units down, the new points are A'(30, 12), B'(30, 52), C'(10, 12).

This is a transformation of (x,y) --> (4x - 10, 4y - 8)

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