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Fynjy0 [20]
3 years ago
7

Please show the work as well for #2

Chemistry
1 answer:
makkiz [27]3 years ago
5 0

Answers:

(a) 508 THz; (b) 337 zJ

Step-by-step explanation:

The formula relating the frequency (f) and wavelength (λ) of a photon is

fλ = c     Divide both sides by λ

f  = c/λ

The formula for the energy of a photon is

E = hf

Data:

c = 2.998 × 10⁸ m·s⁻¹

λ = 590 nm

h = 6.626 × 10³⁴ J·s

Calculations:

(a) <em>Frequency </em>

f = 2.998 × 10⁸/(590 × 10⁻⁹)

 = 5.08 × 10¹⁴ s⁻¹

 = 508 × 10¹² s⁻¹

 = 508 THz

(b) <em>Energy </em>

E = 6.626 × 10⁻³⁴ × 508 × 10¹²

  = 3.37 × 10⁻¹⁹ J

  = 337 × 10⁻²¹ J

  = 337 zJ

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