Anything with a pH level of 3, 2, or 1.
The reaction between copper II chloride and sodium sulfide as well as lead II nitrate and potassium sulfate both produce precipitates.
The solubility of a substance in water is in accordance with the solubility rules. It is possible that a solid product may be formed when two aqueous solutions are mixed together. That solid product is referred to as a precipitate.
Now, we will consider each reaction individually to decode whether or not a precipitate is possible.
- In the first reaction, we have; CuCl2(aq) + Na2S(aq) ---->CuS(s) + 2NaCl(aq). A precipitate (CuS) is formed.
- In the second reaction, Pb(NO3)2(aq) + 2KNO3(aq) ----> PbSO4(s) + KNO3(aq), a precipitate PbSO4 is formed
- In the third reaction, NH4Br(aq) + NaOH(aq) ----->NH3(g) + NaBr(aq) + H2O(l), a precipitate is not formed here.
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Answer:
It's b
Explanation:
I had the same exact question
Answer : The atoms in this compound are Copper(Cu), Chlorine(Cl), Hydrogen(H), Oxygen(O).
Explanation :
The given compound is copper chloride bi-hydrate which is also called as copper (II) chloride dihydrate as it contains two water of crystallisation.
The formula of copper chloride bi-hydrate is .
Therefore, there are 4 atoms in this compound and they are Copper(Cu), Chlorine(Cl), Hydrogen(H) and Oxygen(O).
Answer:
— The molality of chloride ions in 300g of water is. A) 1.00 molal. B) 0.500 molal. C) 0.0553 molal. D) 0.111 molal.