Find the coordinates of the vertex of g(x) = |x + 1| - 2.
2 answers:
Given: g(x) = |x + 1| - 2.
We start at g(x) = |x| at (0, 0)
c < 0 moves it down
y = f(x) + c
2 units down
c > 0 moves it left
y = f(x + c)
1 unit to the left
After the shift, we see the vertex being at (-1, -2) .
Best of Luck!
Answer:
The vertex will be at ( -1,-2)
Step-by-step explanation:
g(x) = |x + 1| - 2.
The vertex of g(x) = |x | is ( 0,0)
y = f(x) + C C < 0 moves it down
y = f(x + C) C > 0 moves it left
We shift this to the left 1 unit and down 2 units
( 0 -1, 0-2)
The vertex will be at ( -1,-2)
You might be interested in
Since p is an obtuse angle & that it's between two acute angles
Hello, one of two<span> fixed points inside an ellipse from which the </span>sum<span> of the </span>distances<span> to any point on the ellipse is constant. </span>
2/3* 3 is 2 so the answer is x=2
Answer:
1.06 sq inches
Step-by-step explanation:
its reasonable come on now
Just think of for example 6x4=24 so the Division problom would be 24 divided by 4 or 6 the answer would be 6 or 4 by