A manufacturer knows that their items have a normally distributed lifespan, with a mean of 12.3 years, and standard deviation of
0.8 years. If you randomly purchase one item, what is the probability it will last longer than 14 years
1 answer:
Answer:
probability of lasting longer = 1.7%
Step-by-step explanation:
We are given:
x' = 14 years
μ = 12.3 years
s = 0.8 years
Thus, let's use the formula for the Z-score value which is;
z = (x' - μ)/s
Thus;
z = (14 - 12.3)/0.8
z = 2.125
From the z-distribution table attached, the p-value is ;
P(x' > 2.125) = 1 - 0.983 = 0.017 = 1.7%
Thus,probability of lasting longer = 1.7%
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