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almond37 [142]
3 years ago
6

The vertices of Triangle PQR have coordinates P(2, 3), Q(3, 8), and R(7, 3). Under which transformation of Triangle PQR are dist

ance and angle measure preserved?
a) (x, y) --> (2x, 3y)
b) (x, y) --> (x + 2, 3y)
c) (x, y) --> (2x, y + 3)
d) (x, y) --> (x + 2, y + 3)
Mathematics
1 answer:
Brut [27]3 years ago
7 0

Answer:

Option d.

Step-by-step explanation:

It is given that vertices of triangle PQR have coordinates P(2, 3), Q(3, 8), and R(7, 3).

We need to find the transformation of Triangle PQR, so that distance and angle measure preserved.

We know that translation is a rigid transformation if the rule of translation is

(x,y)\rightarrow (x+a,y+b)

where, a represents the horizontal shift and b represent the vertical shift.

To for a congruent triangle the coefficients of x and y must be 1.

Only in option d the coefficients of x and y are 1.

(x,y)\rightarrow (x+2,y+3)

Therefore, the correct option is d.

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Quick i dont have time
Volgvan

Answer:

angle SRT = 180 -44 = 136 °

Step-by-step explanation:

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5 0
2 years ago
(2pm^-1q^0)^-4 • 2m ^-1 p^3 / 2pq^2
Montano1993 [528]

Answer:

\dfrac{m^3}{16p^2q^2}

Step-by-step explanation:

Given:

(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}

1.

m^{-1}=\dfrac{1}{m}

2.

q^0=1

3.

2pm^{-1}q^0=2p\cdot \dfrac{1}{m}\cdot 1=\dfrac{2p}{m}

4.

(2pm^{-1}q^0)^{-4}=\left(\dfrac{2p}{m}\right)^{-4}=\left(\dfrac{m}{2p}\right)^4=\dfrac{m^4}{(2p)^4}=\dfrac{m^4}{16p^4}

5.

m^{-1}=\dfrac{1}{m}

6.

2m^{-1} p^3=2\cdot \dfrac{1}{m}\cdot p^3=\dfrac{2p^3}{m}

7.

\dfrac{ 2m^{-1} p^3}{2pq^2}=\dfrac{\frac{2p^3}{m}}{2pq^2}=\dfrac{2p^3}{m}\cdot \dfrac{1}{2pq^2}=\dfrac{p^2}{mq^2}

8.

(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}=\dfrac{m^4}{16p^4}\cdot \dfrac{p^2}{mq^2}=\dfrac{m^3}{16p^2q^2}

8 0
3 years ago
5.
Viktor [21]

Answer:

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3 0
2 years ago
Read 2 more answers
Let z denote a random variable that has a standard normal distribution. Determine each of the probabilities below. (Round all an
Lorico [155]

Answer:

P(Z < 2.37) = 0.9911.

Step-by-step explanation:

We are given that Let z denote a random variable that has a standard normal distribution.

Let Z = a random variable

So, Z ~ Standard Normal(0, 1)

As we know that the standard normal distribution has a mean of 0 and variance equal to 1.

                          Z  =  \frac{X-\mu}{\sigma}  ~ N(0,1)

where, \mu = mean = 0

           \sigma = standard deviation = 1

Now, the probability that z has a value less than 2.37 is given by = P(Z < 2.37)

        P(Z < 2.37) = P(Z < \frac{2.37-0}{1} ) = P(Z < 2.37) = 0.9911

The above probability is calculated by looking at the value of x = 2.37 in the z table which has an area of 0.9911.

4 0
3 years ago
Urgent answer needed pls​
worty [1.4K]

Answer:

48 cm²

Step-by-step explanation:

PTRS is parallelogram with the base length= 8cm and the height as same as the height of ∆SUR.

the height = 2×24/8 = 6cm

so, the area of PTRS= 8×6 = 48 cm²

6 0
2 years ago
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