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irga5000 [103]
3 years ago
7

Under which circumstances would electrons be most likely to be shared equally?

Chemistry
1 answer:
Temka [501]3 years ago
8 0

when atoms of the same element are sharing them

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a) One kmol of N2O4 dissociates at 25℃, 1 atm to form an equilibrium ideal gas mixture of N2O4 and NO2 in which the amount of N2
horsena [70]

Answer:

neq N2O4 = 0.9795 mol.....P = 0.5 atm; T = 25°C

Explanation:

             ni      change    eq.

N2O4    1          1 - x       0.8154.....P = 1 atm; T = 25°C

NO2      0        0 + x          x

∴ x = neq = Peq.V / R.T.....ideal gas mix

if P = 0.5 atm, T = 25°C; assuming: V = 1 L

⇒ x = neq = ((0.5 atm)(1 L))/((0.082 atm.L/K.mol)(298 K))

⇒ x = neq = 0.0205 mol

⇒ neq N2O4 = 1 - x = 1 - 0.0205 = 0.9795 mol

3 0
3 years ago
What compound is formed when 2,2-dimethyloxirane (2-methyl-1,2-epoxypropane) is treated with ethanol containing sulfuric acid
vladimir1956 [14]

Answer:

2-ethoxy-2-methylpropan-1-ol

Explanation:

On this reaction, we have an "<u>epoxide"</u> (2-methyl-1,2-epoxypropane). Additionally, we have <u>acid medium</u> (due to the sulfuric acid H_2SO_4). The acid medium will produce the <u>hydronium ion</u> (H^+). This ion would be attacked by the oxygen of the epoxide. Then a <u>carbocation</u> would be produced, in this case, the most stable carbocation is the <u>tertiary one</u>. Then an <u>ethanol</u> molecule acts as a nucleophile and will attack the carbocation. Finally, a <u>deprotonation </u>step takes place to produce <u>2-ethoxy-2-methylpropan-1-ol</u>.

See figure 1

I hope it helps!

3 0
3 years ago
HELP PLEASEEEEEEEEEEEEEEEEEE I CANT GO CANRVIL IF I CANT PASS THIS THEY WANNA SEE MY GRADES AND THIS WILL HELP ME GET MY GRADES
Daniel [21]

Answer:

3,3453 thank me later

Explanation:

1,3433

4 0
3 years ago
107.854 how many significant
sattari [20]

Answer:

3

Explanation:

look after DP theres 3 digits

6 0
3 years ago
2FeCl3 ---&gt; 2FeCl2 + Cl2
vesna_86 [32]
The correct options are as follows: 
1. In the chemical equation given above, Fe3+  IS REDUCED.
A reduction is a process in which an atom of an element gains an electron and therefore become reduced. In this type of reaction, the positive character of the atom is reduced. Looking at the equation given above, you will notice that, the positive character of Iron is reduced form +3 to +2.

2. In the reaction given above, the chlorine atom is OXIDIZED.
An oxidation is a process in which an atom loses an electron, thereby increasing its oxidation number. In this case, the positive character of the atom is increased. Looking at the chlorine atom given above, you will notice that it has a charge of -1 before and now it has change to neutral, which means that, it has given out the electron it gains earlier.

3. This type of redox reaction can not take place. This is because, in chemical reaction, the chlorine atom is always looking for another element that will donate an electron to it in order to become stable. Thus, chlorine atom easily gain electrons but it can not donate an electron to another element.<span />
8 0
3 years ago
Read 2 more answers
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