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fomenos
3 years ago
5

Ca(MnQ4)2 molar mass

Chemistry
1 answer:
Allisa [31]3 years ago
8 0

Answer:

I think u mean molar mass of ca(Mno4)2

if so it is 277.949 g/ mol

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How many grams of oxygen gas are contained in a 15 L sample at 1.02 atm and 28°C? Please show your work.
vampirchik [111]

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0.019 g.

Explanation:

  • Firstly, we need to find the no. of moles of oxygen gas:
  • We can use the general law of ideal gas: <em>PV = nRT. </em>

where, P is the pressure of the gas in atm (P = 1.02 atm).

V is the volume of the gas in L (V = 15.0 L).

n is the no. of moles of the gas in mol (n = ??? mol).

R is the general gas constant (R = 0.0821 L.atm/mol.K),

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∴ n = PV/RT = (1.02 atm)(15.0 L)/(0.0821 L.atm/mol.K)(301.0 K) = 0.62 mol.

  • To find the mass of oxygen gas, we have:

<em>no. of moles = mass/molar mass.</em>

<em></em>

∴ mass of oxygen = (no. of moles)(molar mass) = (0.62 mol)(32.0 g/mol) = 0.019 g.

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4 years ago
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