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3 years ago

What is the force on an object with a mass of 25 kg and an acceleration of 5 m/s/s? 1 point

Physics

1 answer:

Oduvanchick [21]3 years ago

7 0

Answer:125N

Explanation:

Mass =25kg

Acceleration =5m/s/s

Force=mass x acceleration

Force=25 x 5

Force=125N

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Answer:

$\dot{m_{2}}=0.865 kg/s$

Explanation:

$\dot{m_1}= 0.5kg/s$

from steam tables , at 250 kPa, and at

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we know

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according to energy balance equation

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4 years ago

Three children are struggling and pulling on a single toy. Two of the children, Abe and Barry, are EACH (individually) pulling w

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Solution :

c). $\vec{F}_A =$ force applied by Abe

$\vec{F}_B =$ force applied by Barry

$\vec{F}_E =$ force applied by Eric

$\vec{F}_R =$ Resultant force

$\vec{F}_A$ in the vector form can be written as :

$\vec{F}_A = 0 \hat{i} + 60 \hat{j}$

$\vec{F}_B$ in the vector form can be written as :

$\vec{F}_B = 60 \hat{i} + 0 \hat{j}$

The resultant,

$\vec{F}_R= \vec{F}_A+\vec{F}_B$

$=(0 \hat i + 60 \hat j)+(60 \hat i + 0\hat j)$

$=60 \hat i + 60 \hat j$

$|\vec{F}_R| = \sqrt{60^2+60^2}$

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d). As the three forces are in equilibrium, therefore,

$|\vec F_E| = |\vec F_R|$

$|\vec F_E| =84.853 \ N$

e). The direction of the force exerted by Eric is exactly opposite to the direction of the resultant force.

The direction of the resultant force is :

$\theta = \tan ^{-1}\left(\frac{F_y}{F_x}\right)$

$= \tan ^{-1}\left(\frac{60}{60}\right)$

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The direction of the force E is 45° west or 45° south west.

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