Answer: The final temperature is 470K
Explanation: Using the relation;
Q= ΔU +W
Given, n = 2mol
Initial temperature T1= 345K
Heat =Q= 2250J
Workdone=W=-870J(work is done on gas)
T2 =Final temperature =?
ΔU =3/2nR(T2-T1)
ΔU=3/2 × 2 ×8.314 (T2 - 345)
ΔU=24.942(T2-345)
Therefore Q = 24.942(T2-345)+ (-870)
2250=24.942(T2-345)+ (-870)
125.09=(T2-345)
T2 =470K
Therfore the final temperature is 470K
Answer:

Explanation:
In all atoms, the number of protons = number of electrons, as a result the atom is neutral. Losing or gaining electrons will make the atom electrically charged and we call an electrically charged atom an ion.
Ca 2+ would be the symbol because losing two negative electrons makes calcium's nucleus more positive by two protons.
Answer: Given:
Initial velocity= 36km/h=36x5/18=10m/s
Final velocity =54km/h=54x5/18=15m/s
Time =10sec
Acceleration = v-u/ t
=15-10/10=5/10=1/2=0.5 m/s2
Distance =s=?
From second equation of motion:
S=ut +1/2 at^2
=10*10+1/2*0.5*10*10
=100+25
=125m
So distance travelled 125m
Hope it helps you
Explanation:
F =(frac{1}{4{pi}{varepsilon}_o}) x (frac {q_1q_2}{r^2})
F =(frac {5 {times} 10 {times} 8 {times} 10}{0.002 {times} 0.002}) x 9 x 10
F = 900N
Answer:
1178 nm
Explanation:
We are given that
Wavelength of light=

We have to find the thickness of spacer if five dark fringes are observed between the edges of the glass.
Suppose that first dark fringe and fifth dark fringe near spacer, then the path length of light is 4 times the wavelength of light.
The light passes through air film is two times then the change in air film thickness from one edge to other is two times the wavelength of light.
Change in air film thickness from one edge to other edge is same as the thickness of spacer.
Therefore, thickness of spacer=
Thickness of spacer=
m
Thickness of spacer=1178 nm
Hence, the thickness of spacer=1178 nm