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Gemiola [76]
3 years ago
14

The range and standard deviation of a distribution are __________.

Physics
2 answers:
Zolol [24]3 years ago
6 0
The correct answer is B) Measures of variability. Hope this helps.
Maksim231197 [3]3 years ago
5 0

Answer:

B) Measures of variability

Explanation:

Edg 2020

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Two moles of an ideal monatomic gas are at a temperature of 345 K. Then, 2250 J of heat is added to the gas, and 870 J of work i
Lapatulllka [165]

Answer: The final temperature is 470K

Explanation: Using the relation;

Q= ΔU +W

Given, n = 2mol

Initial temperature T1= 345K

Heat =Q= 2250J

Workdone=W=-870J(work is done on gas)

T2 =Final temperature =?

ΔU =3/2nR(T2-T1)

ΔU=3/2 × 2 ×8.314 (T2 - 345)

ΔU=24.942(T2-345)

Therefore Q = 24.942(T2-345)+ (-870)

2250=24.942(T2-345)+ (-870)

125.09=(T2-345)

T2 =470K

Therfore the final temperature is 470K

5 0
3 years ago
The chemical symbol for the element calcium is Ca. What would be the symbol representing calcium atoms that have lost two electr
Kazeer [188]

Answer:

ca^{2 + }

Explanation:

In all atoms, the number of protons = number of electrons, as a result the atom is neutral. Losing or gaining electrons will make the atom electrically charged and we call an electrically charged atom an ion.

Ca 2+ would be the symbol because losing two negative electrons makes calcium's nucleus more positive by two protons.

5 0
3 years ago
Read 2 more answers
1) A train accelerates from 36 km/hr to 54 km/hr in 10<br> s. Find acceleration?
Crank

Answer: Given:

Initial velocity= 36km/h=36x5/18=10m/s

Final velocity =54km/h=54x5/18=15m/s

Time =10sec

Acceleration = v-u/ t

=15-10/10=5/10=1/2=0.5 m/s2

Distance =s=?

From second equation of motion:

S=ut +1/2 at^2

=10*10+1/2*0.5*10*10

=100+25

=125m

So distance travelled 125m

Hope it helps you

3 0
4 years ago
What is the force of repulsion between two points positive charges 5 and 8 separated at a distance of 0.02m apart
Zinaida [17]

Explanation:

F =(frac{1}{4{pi}{varepsilon}_o}) x (frac {q_1q_2}{r^2})

F =(frac {5 {times} 10 {times} 8 {times} 10}{0.002 {times} 0.002}) x 9 x 10

F = 900N

4 0
2 years ago
A wedge shaped air film is made between two sheets of glass using a spacer at one end of the glass sheets. If light of wavelengt
pychu [463]

Answer:

1178 nm

Explanation:

We are given that

Wavelength of light=\lambda=589nm=589\times 10^{-9} m

1nm=10^{-9} m

We have to find the thickness of spacer if five dark fringes are observed between the edges of the glass.

Suppose that first dark fringe and fifth dark fringe near spacer, then the path length of light is 4 times the wavelength of light.

The light passes through air film is two times  then the change in air film thickness  from one edge to other is two times the wavelength of light.

Change in air film thickness  from one edge to other edge  is same as the thickness of spacer.

Therefore, thickness of spacer=2\lambda

Thickness of spacer=2\times 589\times 10^{-9}m

Thickness of spacer=1178 nm

Hence, the thickness of spacer=1178 nm

8 0
3 years ago
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