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Genrish500 [490]
3 years ago
7

Suppose that a group of 10 students are to be assigned to four dorm rooms: a single, a double, a triple and a quad. How many way

s are there are making the assignments? Choose the best answer.
Mathematics
1 answer:
Nesterboy [21]3 years ago
6 0

Answer:

Total number of ways to select all sstudent to make assignment = 10×36×70×1 = 25200

Step-by-step explanation:

We have given number of students = 10

These 10 students are assigned to four dorm rooms a single, a double, a triple and a quad

So number of ways to assigned single student =^{10}C_1=\frac{10!}{1!9!}=10\\

Now left student = 10 -1 = 9

So number of ways to assigned double student =^{9}C_2=\frac{9!}{2!7!}=36

Now left student = 9-2 = 7

So number of ways to assigned triple student =^{7}C_3=\frac{7!}{2!4!}==70

Now left student = 7 - 3 = 4

So number of ways to assigned quad student =^{4}C_4=\frac{4!}{4!0!}=1

So total number of ways to select all sstudent to make assignment = 10×36×70×1 = 25200

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Sophie [7]
The answer is 35 cm I think that’s right not certain
3 0
3 years ago
6x+3y=15 for y. What does y equal if x=2? If x=5?
IrinaVladis [17]
If x=2, the equation would be 6 (2) + 3y = 15.

This simplifies to 12 +3y = 15. Subtract 12 from both sides and you get 3y = 3. Divide both sides by 3 and you get y = 1. 

So if x = 2, y =1 

If x = 5, the equation becomes  6 (5) + 3y = 15.

This simplifies to 30 + 3y = 15. Subtract 30 from both sides and you get 3y = -15. Divide both sides by 3 and you get y = -5. 

So if x =5, y = -5. 

I hope this helps!

6 0
4 years ago
what key feature(s) can be easily identified from factored form? explain how each key feature is related to the roller coaster.
Ulleksa [173]

Answer:

Step-by-step explanation:

With a factor of (t - 1) we know that zero (ground level) is reached at 1 second from an initial height of (0 - 1)(0 - 1)(0 - 11)(0 - 13)/3 = -1•-1•-11•-13 / 3 = 47⅔ meters at t = 0

As we have <em>two </em>factors of (t - 1) we know the track does not go underground at t = 1, but rises again.

At t = 11 seconds, the car has again returned to ground level, but as we only have a single factor of (t - 11) the car plunges below ground level and returns to above ground level at t = 13 seconds due to the single factor of (t - 13)

we can estimate that the car is the deepest below ground level halfway between 11 and 13 s, so at t = 12. At that time, the depth will be about (12 - 1)(12 - 1)(12 - 11)(12 - 13) / 3 = -(11²/3) = - 40⅓ m.

we can estimate that the car is the highest above ground level halfway between 1 and 11 s, so at t = 6s. At that time, the height will be about (6 - 1)(6 - 1)(6 - 11)(6 - 13) / 3 = 5²•-5•-7 / 3 = 291⅔  m.

It's obvious that the roller coaster car had significant initial velocity at t = 0 to achieve that altitude from an initial height of 47⅔ m

6 0
3 years ago
1 3. A tennis court for singles pay is 78 feet and 27 feet wide The court for doubles pay has the same length but is 9 feet Wide
galina1969 [7]
Lets calculate areas:
single area = (78)(27) = 2106 ft^2
doubles area = (78)(27 + 9) = (78)(36) = 2808<span> ft^2</span>
junior area = (36)(18) = 648 ft^2
10&under area = (78 - 18)(27) = (60)(27) = 1620 <span>ft^2
</span>
The doubles area is bigger than the singles by 2808 - <span>2106 = 702 ft^2</span>

The singles area is bigger than the juniors by 2106 - 648 = 1458 <span>ft^2

</span>The singles area is bigger than the 10&under by 2106 - 1620 = 486 <span>ft^2</span>
8 0
3 years ago
Help me please, match the number to the letter​
kenny6666 [7]

Answer:  1b  2c  3e?  4d  5a

<u>Step-by-step explanation:</u>

There are 2 items that need to be checked.  

  1. The midpoint of the coordinates is the center of the circle
  2. The diameter of the coordinates is the diameter of the circle.

Midpoint:

Midpoint = \bigg(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\bigg)\\\\\\1)\ \bigg(\dfrac{-4+2}{2},\dfrac{-1+10}{2}\bigg)=\bigg(\dfrac{-2}{2},\dfrac{9}{2}\bigg)=(-1, 4.5)\implies \text{equation b}\\\\\\2)\ \bigg(\dfrac{1+7}{2},\dfrac{3-10}{2}\bigg)=\bigg(\dfrac{8}{2},\dfrac{-7}{2}\bigg)=(4, -3.5)\implies \text{equation c}\\\\\\3)\ \bigg(\dfrac{4-8}{2},\dfrac{-2+6}{2}\bigg)=\bigg(\dfrac{-4}{2},\dfrac{4}{2}\bigg)=(-2,2 )\implies \text{none of the equations}

4)\ \bigg(\dfrac{6-4}{2},\dfrac{3-13}{2}\bigg)=\bigg(\dfrac{2}{2},\dfrac{-10}{2}\bigg)=(1, -5)\implies \text{equation d}\\\\\\5)\ \bigg(\dfrac{7-1}{2},\dfrac{5+8}{2}\bigg)=\bigg(\dfrac{6}{2},\dfrac{13}{2}\bigg)=(3, 6.5)\implies \text{equation a}

Diameter:

distance between coordinates = 2√r² (from circle equation)

\text{formula for coordinates is: }d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\\\1)\ \text{Coordinates: } d=\sqrt{(-4-2)^2+(-1-10)^2}=\sqrt{36+121}=12.5\\b)\ \text{Circle: }2\sqrt{39.25}=12.5\\\\\\2)\ \text{Coordinates: } d=\sqrt{(1-7)^2+(3+10)^2}=\sqrt{36+169}=14.3\\c)\ \text{Circle: }2\sqrt{51.25}=14.3\\\\\\4)\ \text{Coordinates: } d=\sqrt{(6+4)^2+(3+13)^2}=\sqrt{100+256}=18.9\\d)\ \text{Circle: }2\sqrt{89}=18.9

5)\ \text{Coordinates: } d=\sqrt{(7+1)^2+(5-8)^2}=\sqrt{64+9}=8.5\\a)\ \text{Circle: }2\sqrt{18.25}=8.5

Check:

Graph to confirm your answers are correct (see attached)

8 0
3 years ago
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