The answer is 35 cm I think that’s right not certain
If x=2, the equation would be 6 (2) + 3y = 15.
This simplifies to 12 +3y = 15. Subtract 12 from both sides and you get 3y = 3. Divide both sides by 3 and you get y = 1.
So if x = 2, y =1
If x = 5, the equation becomes 6 (5) + 3y = 15.
This simplifies to 30 + 3y = 15. Subtract 30 from both sides and you get 3y = -15. Divide both sides by 3 and you get y = -5.
So if x =5, y = -5.
I hope this helps!
Answer:
Step-by-step explanation:
With a factor of (t - 1) we know that zero (ground level) is reached at 1 second from an initial height of (0 - 1)(0 - 1)(0 - 11)(0 - 13)/3 = -1•-1•-11•-13 / 3 = 47⅔ meters at t = 0
As we have <em>two </em>factors of (t - 1) we know the track does not go underground at t = 1, but rises again.
At t = 11 seconds, the car has again returned to ground level, but as we only have a single factor of (t - 11) the car plunges below ground level and returns to above ground level at t = 13 seconds due to the single factor of (t - 13)
we can estimate that the car is the deepest below ground level halfway between 11 and 13 s, so at t = 12. At that time, the depth will be about (12 - 1)(12 - 1)(12 - 11)(12 - 13) / 3 = -(11²/3) = - 40⅓ m.
we can estimate that the car is the highest above ground level halfway between 1 and 11 s, so at t = 6s. At that time, the height will be about (6 - 1)(6 - 1)(6 - 11)(6 - 13) / 3 = 5²•-5•-7 / 3 = 291⅔ m.
It's obvious that the roller coaster car had significant initial velocity at t = 0 to achieve that altitude from an initial height of 47⅔ m
Lets calculate areas:
single area = (78)(27) = 2106 ft^2
doubles area = (78)(27 + 9) = (78)(36) = 2808<span> ft^2</span>
junior area = (36)(18) = 648 ft^2
10&under area = (78 - 18)(27) = (60)(27) = 1620 <span>ft^2
</span>
The doubles area is bigger than the singles by 2808 - <span>2106 = 702 ft^2</span>
The singles area is bigger than the juniors by 2106 - 648 = 1458 <span>ft^2
</span>The singles area is bigger than the 10&under by 2106 - 1620 = 486 <span>ft^2</span>
Answer: 1b 2c 3e? 4d 5a
<u>Step-by-step explanation:</u>
There are 2 items that need to be checked.
- The midpoint of the coordinates is the center of the circle
- The diameter of the coordinates is the diameter of the circle.
Midpoint:


Diameter:
distance between coordinates = 2√r² (from circle equation)


Check:
Graph to confirm your answers are correct (see attached)