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2 years ago

Tamara is bringing refreshments to a

Mathematics

1 answer:

andrew-mc [135]2 years ago

7 0

She should buy 5 liters of juice.

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Staples pays George Nagovsky an annual salary of $36,000. Today, George's boss informs him that he will received a $4,600 raise.

konstantin123 [22]

George will receive 13% of his old income

3 0

3 years ago

Solve for the equation of value of x(show your solution)

sertanlavr [38]

Answer:

2. ) {25}^{2x} - 1 = {125}^{3x} + 4

=> {25}^{2x} = {125}^{3x} + 4 +1

=> {(5)^(2)}^{2x} = {(5)^(3)}^{3x} + {5}^{1}

=> {5}^{4x} = {5}^{9x} + {5}^{1}

=> 4x = 9x + 1

=> 4x - 9x = 1

=> - 5x = 1

=> x = 1/-5

7 0

3 years ago

Question 7: Find the value of x. The numbers below are in degrees.<br> 140<br> S<br> 50<br> 20

Lyrx [107]

Given:

A figure.

To find:

The value of x.

Solution:

Draw two parallel lines as shown in the below figure.

If a transversal line intersect two parallel lines, then alternate interior angles are same.

$a=20$ (Alternate interior angle)

$d=b$ (Alternate interior angle) ...(i)

The value of angle d is

$d=50-a$

$d=50-20$

$d=30$

Using (i), we get

$b=30$

If a transversal line intersect two parallel lines, then same sides interior angles are supplementary angles.

$c+140=180$

$c=180-140$

$c=40$

Now,

$x=b+c$

$x=30+40$

$x=70$

Therefore, the value of x is 70.

8 0

2 years ago

How to simplify (-4)(-4)

DedPeter [7]

Answer:

How to simplify (-4)(-4)

-4×-4=16

5 0

3 years ago

Read 2 more answers

A research company desires to know the mean consumption of milk per week among males over age 25. A sample of 650 males over age

Advocard [28]

Answer:

$3.3\leq x\leq 3.5$

Step-by-step explanation:

The 95% confidence interval can be calculated as:

$x'-z_{\alpha/2}\frac{s}{\sqrt{n}} \leq x\leq x'+z_{\alpha/2}\frac{s}{\sqrt{n}}$

Where $x$ is the mean consumption of milk, $x'$ is the sample mean, $s$ is the population standard deviation, $n$ is the size of the sample, $\alpha$ is 5% and $z_{\alpha /2}$ is the z-value that let a probability of $\alpha /2$ on the right tail.

So, replacing $x'$ by 3.4 liters, $s$ by 1.3 liters, n by 650 and $z_{\alpha /2}$ by 1.96, we get that the 95% confidence interval is equal to:

$3.4-(1.96*\frac{1.3}{\sqrt{650}})\leq x\leq 3.4+(1.96*\frac{1.3}{\sqrt{650}}) \\3.4-0.1\leq x\leq 3.4+0.1\\3.3\leq x\leq 3.5$

4 0

3 years ago

Read 2 more answers