To the nearest tenth = 4.4 and to the nearest whole number is 4. Whatever estimation it asks you.
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Answer: False</h3>
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Explanation:
I'm assuming you meant to type out
(y-2)^2 = y^2-6y+4
This equation is not true for all real numbers because the left hand side expands out like so
(y-2)^2
(y-2)(y-2)
x(y-2) .... let x = y-2
xy-2x
y(x)-2(x)
y(y-2)-2(y-2) ... replace x with y-2
y^2-2y-2y+4
y^2-4y+4
So if the claim was (y-2)^2 = y^2-4y+4, then the claim would be true. However, the right hand side we're given doesn't match up with y^2-4y+4
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Another approach is to pick some y value such as y = 2 to find that
(y-2)^2 = y^2-6y+4
(2-2)^2 = 2^2 - 6(2) + 4 .... plug in y = 2
0^2 = 2^2 - 6(2) + 4
0 = 4 - 6(2) + 4
0 = 4 - 12 + 4
0 = -4
We get a false statement. This is one counterexample showing the given equation is not true for all values of y.
Answer:
the answer is 9c+63
Step-by-step explanation:
Omg that so nice I love this app sm
Answer:
(a) center: (0, 0); radius: 4
(b) center: (8, -3); radius: 10
(c) center: (-2, -7); radius: 7
(d) center: (6, 0); radius: 1
(e) center: (0, 0); radius: 5
(f) center: (3, 8); radius: 8
Step-by-step explanation:
In the figure attached, the complete question is shown.
Equation of a circle with center (h, k) and radius r:
(x - h)² + (y - k)² = r²
