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kow [346]
3 years ago
13

Can someone help me with me with my most recent question please

Mathematics
1 answer:
mojhsa [17]3 years ago
8 0

Answer:

no I can't

Step-by-step explanation:

im a dum dum, sorry.

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The number 1,254 is divisible by all of the following, except _____.<br><br> 6<br> 2<br> 3<br> 9
Orlov [11]

Answer:

The number 1,254 is divisible by all of the following, except 9

4 0
3 years ago
Do these two statements contradict
myrzilka [38]
I don't think so because they're different things!
5 0
2 years ago
Which of the following is a correct tangent ratio for the figure?
Ludmilka [50]

Answer:

tan 76 = 24/8

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

tan theta = opp /adj

tan 76 = 24/8

3 0
3 years ago
Been trying at this can't please help lol
xz_007 [3.2K]

To add or sum this arrary, beg ∈ {array} {r} 37 \202\ + 160/ ∈  end {array} gives <u>A) 399</u>.

<h3>What is an array?</h3>

An array is a data structure made up of some elements.

The sum of all elements in an array is found by adding up the elements in the array.

<h3>Data and Calculations:</h3>

Elements of the array = 37, 202, and 160

The sum of the array, 37 + 202 + 160 = 399

Thus, to add or sum this arrary, beg ∈ {array} {r} 37 \202\ + 160/ ∈  end {array} gives <u>A) 399</u>.

Learn more about arrays at brainly.com/question/23698059

#SPJ1

<h3>Question:</h3>

Add beg ∈ {array} {r} 37 \202\ + 160/ ∈  end {array}

<h3>Answer Options:</h3>

A) 399

B) 389

C) 400

D) 409

4 0
1 year ago
GEOMETRY!!!! K' (6,5) is the image of K after a reflection in the line y=2. what are the coordinates of K
frutty [35]

Given:

The coordinates of point K' are (6,5).

K' is the image of K after a reflection in the line y=2.

To find:

The coordinates of point K.

Solution:

Let the coordinates of point K are (a,b).

If a figure is reflected over the line y=2, then

(x,y)\to (x,2(2)-y)

(x,y)\to (x,4-y)

Using this formula, the coordinates of image of K are

K(a,b)\to K'(a,4-b)

The coordinates of point K' are (6,5).

K'(a,4-b)=K'(6,5)

On comparing both sides, we get

a=6\text{ and }4-b=5

a=6\text{ and }-b=5-4

a=6\text{ and }-b=1

a=6\text{ and }b=-1

Therefore, the coordinates of point K are (6,-1).

3 0
3 years ago
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