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Aloiza [94]
2 years ago
7

Complete all the problems. Use the two-way-table to answer the questions.

Mathematics
1 answer:
marusya05 [52]2 years ago
3 0

Answer:

Im sorry im not to familiar with this. But I believe the answer is 16

Step-by-step explanation:

16 out of 29

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A store is advertising a 25% off sale. Mikale purchases a swimming pool for $225. What was the original price of the pool?
DIA [1.3K]

Answer:

B

Step-by-step explanation:

7 0
3 years ago
What is the area of a circle whose equation is (x-3)² + (y + 1) ² =81?
kupik [55]
Okay, first, given the equation, we need to find out what the radius of the circle is. Let us state the general equation of a circle: 

\frac{(x-x_{1})^2}{r^2}+ \frac{(y-y_{1})_^2}{r^2}=1

Where (x_{1}, y_{1}) is the centre of the circle. In this case, we don't need to know the centre. Just the radius. 

Let us start by converting the equation into standard for, which I typed above. Divide both sides by 81. 

\frac{(x-3)^2}{81}+ \frac{(y+1)^2}{81}=1

Great! We now know the radius of the circle. It is \sqrt{81} because it is the bottom fraction. Now we know that the radius is 9. 

So now lets input this into the area of circle formula: 

A=πr^2 

Now we insert our radius. 

A=9^2π 

=A=81π 

You can convert that into a decimal if you wish. 

Hope this helped!

~Cam943, Moderator
4 0
3 years ago
You are given the sample mean and the population standard deviation. Use this information to construct the​ 90% and​ 95% confide
FrozenT [24]

Question:

You are given the sample mean and the population standard deviation. Use this information to construct the​ 90% and​ 95% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals. If​ convenient, use technology to construct the confidence intervals. A random sample of 45 home theater systems has a mean price of ​$114.00. Assume the population standard deviation is ​$15.30. Construct a​ 90% confidence interval for the population mean.

Answer:

At the 90% confidence level, confidence interval = 110.2484 < μ < 117.7516

At the 95% confidence level, confidence interval = 109.53 < μ < 118.48

The 95% confidence interval is wider

Step-by-step explanation:

Here, we have

Sample size, n = 45

Sample mean, \bar x = $114.00

Population standard deviation, σ = $15.30

The formula for Confidence Interval, CI is given by the following relation;

CI=\bar{x}\pm z\frac{\sigma}{\sqrt{n}}

Where, z is found for the 90% confidence level as ±1.645

Plugging in the values, we have;

CI=114\pm 1.645 \times \frac{15.3}{\sqrt{45}}

or CI: 110.2484 < μ < 117.7516

At 95% confidence level, we have our z value given as z = ±1.96

From which we have CI=114\pm 1.96 \times \frac{15.3}{\sqrt{45}}

Hence CI: 109.53 < μ < 118.48

To find the wider interval, we subtract their minimum from the maximum as follows;

90% Confidence level: 117.7516 - 110.2484 = 7.5

95% Confidence level: 118.47503 - 109.5297 = 8.94

Therefore, the 95% confidence interval is wider.

8 0
3 years ago
Read 2 more answers
Suppose you deposit ​$600 in a bank account with a simple interest rate of 2.5​%. You want to keep your deposit in the bank long
8090 [49]

Answer:

120/2.5%

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
Eric has $25 to purchase magazines and to pay for his lunch. Each
faust18 [17]

Answer:

B

Step-by-step explanation:

The maximum amount Eric can spend on magazines is $25 less the cost of lunch, $15.

The appropriate inequality sign would be less than since he cannot spend more than $25.

Also, the amount he can spend on magazines would be what is left after paying for lunch.

So the correct inequality is 4m - 15 < 25

8 0
2 years ago
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