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3 years ago

-3 + 4x = 25 help mee

Mathematics

2 answers:

Hitman42 [59]3 years ago

7 0

-3+4x+=25
4x=25+3
4x=28
4x=4
x=7

alexdok [17]3 years ago

5 0

Answer:

are u solving for x if so then

x=7

Step-by-step explanation:

hope this helps ...brainliest please!

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What is 0.84 as a fraction in simplest form

tatyana61 [14]

84/100. 42/50. 21/25. And there not sure though

8 0

3 years ago

Find the coordinates of the vertex of the following parabola algebraically. Write your answer as an (x,y)(x,y) point.

Serga [27]

Answer:

(8,-3)

Step-by-step explanation:

The given parabola is

$y = - 3 {x}^{2} + 48x - 195$

We factor -3 from the first two terms to get:

$y = - 3( {x}^{2} - 16x) - 195$

Add and subtract the square of half the coefficient of x

$y = - 3( {x}^{2} - 16x + 64) + 3 \times 64- 195$

$y = - 3 {(x - 8)}^{2} + 192 - 195$

We simplify to get:

$y = - 3 {(x - 8)}^{2} - 3$

We compare this to y=a(x-h)²+k,

The vertex is (h,k)=(8,-3)

3 0

3 years ago

Julius sells two robots a small one and a larger model. the price for the smaller robot is X and the price for the large robot i

Mademuasel [1]

Answer:

15x + 42y = $13 050

Step-by-step explanation:

hope that helped :)

8 0

3 years ago

Lizzie rolls two dice. What is the probability that the sum of the dice is:

zhenek [66]

Answer:

$A.\ \dfrac{1}{3}\\B.\ \dfrac{5}{12}\\C.\ \dfrac{7}{36}\\$

Step-by-step explanation:

Total outcomes possible: 36

A. Divisible by 3

Possible options are:

3, 6, 9 and 12.

Possible outcomes for 3 are: {(1,2), (2,1)} Count 2

Possible outcomes for 6 are: {(1,5), (2,4), (3,3), (5,1),(4,2)} Count 5

Possible outcomes for 9 are: {(3,6), (4,5), (5,4),(6,3)} Count 4

Possible outcomes for 12 are: {(6,6)} Count 1

Total count = 2 + 5 + 4 + 1 = 12

Probability of an event E can be formulated as:

$P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}$

$P(A) = \dfrac{12}{36} = \dfrac{1}{3}$

B. Less than 7:

Possible sum can be 2, 3, 4, 5, 6

Possible cases for sum 2: {(1,1)} Count 1

Possible cases for sum 3: {(1,2), (2,1)} Count 2

Possible cases for sum 4: {(1,3), (3,1), (2,2)} Count 3

Possible cases for sum 5: {(1,4), (2,3), (3,2),(4,1)} Count 4

Possible cases for sum 6: {(1,5), (2,4), (3,3), (5,1),(4,2)} Count 5

Total count = 1 + 2 + 3 + 4 + 5 = 15

$P(B) = \dfrac{15}{36} = \dfrac{5}{12}$

C. Divisible by 3 and less than 7:

$P(A \cap B) = \dfrac{n(A\cap B)}{\text{Total Possible outcomes}}$

Here, common cases are:

Possible outcomes for 3 are: {(1,2), (2,1)} Count 2

Possible outcomes for 6 are: {(1,5), (2,4), (3,3), (5,1),(4,2)} Count 5

$P(A \cap B) = \dfrac{7}{\text{36}}$

5 0

3 years ago

Please explain how you got this answer.

Tema [17]

150 times

out of the first 5 cards, there is a 3/5 chance of drawing a yellow.
if you replace the card and draw again, you still have a 3/5 chance of drawing a yellow card.
keep doing this process for 250 draws, each draw will always have 3/5 chance of drawing a yellow card.

so 3/5 +3/5 +3/5 +... (250 times) = 250 x 3/5 = 150

3 0

3 years ago