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jasenka [17]
3 years ago
14

20 Points Help Solve for y. Enter your answer in the box. y =

Mathematics
2 answers:
Oksana_A [137]3 years ago
8 0
It’s an equilateral triangle so all of the triangle angles add up to 180 and since it’s equilateral each angle is 60 degrees. Setting 8y-4=60, 8y=64, thus y=8 degrees.
Tema [17]3 years ago
5 0

Answer:

Just took the test the answers are down below!!

Step-by-step explanation:

I got it right and I hope this helps :)))

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∠C and ​ ∠D ​ are vertical angles with m∠C=−3x+58 and m∠D=x−2 .<br><br><br><br> What is m∠D ?
11111nata11111 [884]
Vertical angles are equal

-3x + 58 = x - 2
-3x - x = -2 - 58
-4x = - 60
x = -60/-4
x = 15

m < D = x - 2....15 - 2 = 13 <====
m < C = -3x + 58....-3(15) + 58 = 13 
4 0
3 years ago
Read 2 more answers
On the packaging for a triangular sail, the edge measurements for the sail are listed as
Colt1911 [192]

Answer: It is an obtuse triangle I think beause more than one side is more than a 90 degree angle

Step-by-step explanation:

4 0
2 years ago
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The price of parking for 2 hours or less at the airport is increasing
fredd [130]

Answer:

it increased 50%

Step-by-step explanation:

5 / 2.5 = 2

100 / 2 = 50%

5 0
3 years ago
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A uniform distribution is defined over the interval from 6 to 10.
scoundrel [369]
Are you given an equation?
6 0
3 years ago
Given: cos θ=-4/5, sin x = -12/13, θ is in the third quadrant, 
USPshnik [31]

By definition of tangent,

tan(2<em>θ</em>) = sin(2<em>θ</em>) / cos(2<em>θ</em>)

Recall the double angle identities:

sin(2<em>θ</em>) = 2 sin(<em>θ</em>) cos(<em>θ</em>)

cos(2<em>θ</em>) = cos²(<em>θ</em>) - sin²(<em>θ</em>) = 2 cos²(<em>θ</em>) - 1

where the latter equality follows from the Pythagorean identity, cos²(<em>θ</em>) + sin²(<em>θ</em>) = 1. From this identity we can solve for the unknown value of sin(<em>θ</em>):

sin(<em>θ</em>) = ± √(1 - cos²(<em>θ</em>))

and the sign of sin(<em>θ</em>) is determined by the quadrant in which the angle terminates.

<em />

We're given that <em>θ</em> belongs to the third quadrant, for which both sin(<em>θ</em>) and cos(<em>θ</em>) are negative. So if cos(<em>θ</em>) = -4/5, we get

sin(<em>θ</em>) = - √(1 - (-4/5)²) = -3/5

Then

tan(2<em>θ</em>) = sin(2<em>θ</em>) / cos(2<em>θ</em>)

tan(2<em>θ</em>) = (2 sin(<em>θ</em>) cos(<em>θ</em>)) / (2 cos²(<em>θ</em>) - 1)

tan(2<em>θ</em>) = (2 (-3/5) (-4/5)) / (2 (-4/5)² - 1)

tan(2<em>θ</em>) = 24/7

4 0
3 years ago
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