12/3 or the same thing as ur question but just add a division sign, eg. difference of two and one that would be 2-1
The quotient if the equation is x3
Answer:
H = V0y t - 1/2 g t^2 equation for vertical height of object with initial speed (V0y = V0 sin theta)
If H is to be considered an absolute value from t = 0
h = H + 3 = V0y t - 1/2 g t^2 + 3 where h is height from ground