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Murljashka [212]
3 years ago
9

Item 3

Mathematics
2 answers:
Zina [86]3 years ago
7 0

Answer:

22

Step-by-step explanation:

Marina CMI [18]3 years ago
7 0
次沒這月山木口尸火尸火山尸十金竹火土木土金
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what is the rate of change for the linear relationship modeled in the table? x y −1 10 1 9 3 8 5 7 -1/2 0 1/2 2
Vesnalui [34]

Answer:

Rate of change for the linear relationship modeled is \dfrac{-1}{2}

Step-by-step explanation:

As the there is a linear relationship in the points, so all these points will be on a single straight line. Hence the slope will be same throughout all the points.

We know that, the slope of the line joining (x₁, y₁) and (x₂, y₂) is,

m=\dfrac{y_2-y_1}{x_2-x_1}

Putting the points as (-1, 10) and (1, 9), we get

m=\dfrac{9-10}{1-(-1)}

=\dfrac{9-10}{1+1}

=\dfrac{-1}{2}

Rate of change is the slope of the line joining all these points.

7 0
3 years ago
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How do you solve the equation 8-5w= -37<br>​
loris [4]

Answer:

w=25/4=6.50

Step-by-step explanation:

4 0
3 years ago
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Which is the equation of a line perpendicular to the line y
guajiro [1.7K]

Answer:

is b

Step-by-step explanation:

6 0
3 years ago
If vertex U is located at (-4, 5) and vertex V is located at (-6, 2), then vertex U′ is located at
elixir [45]

The vertex U' is located at (-4, -5)

<h3>How to determine the location of U'?</h3>

The vertices are given as:

U = (-4, 5)

V = (-6, 2)

The rule of transformation is given as:

Reflection across the x-axis

This is represented as:

(x, y) => (x, -y)

So, we have:

U' = (-4, -5)

Hence, the vertex U' is located at (-4, -5)

Read more about transformation at:

brainly.com/question/11707700

#SPJ1

<u>Complete question</u>

Quadrilateral UVWX is reflected over the x-axis to form quadrilateral U′V′W′X′. If vertex U is located at (-4, 5) and vertex V is located at (-6, 2), then vertex U′ is located at

7 0
2 years ago
Factor the perfect square trinomial.<br> x(Squared)+4x+4
Nataliya [291]

Answer:

(x + 2)²

Step-by-step explanation:

Given

x² + 4x + 4 ← is a perfect square of the form

(x + a)² = x² + 2ax + a²

Compare like terms

a² = 4 ⇒ a = \sqrt{4} = 2, thus

x² + 4x + 4 = (x + 2)²

6 0
3 years ago
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