2.03 *24 = 48.72................
Answer:
13.567%
Step-by-step explanation:
We solve the above question, using z score formula
z = (x-μ)/σ, where
x is the raw score = 23.1 ounces
μ is the population mean = 22.0 ounces
σ is the population standard deviation = 1.0 ounce
More than = Greater than with the sign = >
Hence, for x > 23.1 ounces
z = 23.1 - 22.0/1.0
= 1.1
Probability value from Z-Table:
P(x<23.1) = 0.86433
P(x>23.1) = 1 - P(x<23.1)
P(x>23.1) = 1 - 0.86433
P(x>23.1) = 0.13567
Converting to percentage
= 0.13567 × 100
= 13.567%
Therefore, the percentage of regulation basketballs that weigh more than 23.1 ounces is 13.567%
7. -8/3
8. 4/35
9. -21/50
10. 35/64
11.-25/54
Answer:
(2,8)
x = 2
y = 8
Step-by-step explanation:
<u>The steps are shown in the picture</u>
Answer:
Step-by-step explanation:
−7−4p+5
−4p+(−7+5)
Ans
−4p−2
