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Harrizon [31]
3 years ago
10

Six friends each use a $2.00 off coupon to buy themselves a movie ticket. They spend a total of 42. What is the price of one mov

ie ticket without the coupon
Mathematics
1 answer:
attashe74 [19]3 years ago
5 0

Answer:

5

Step-by-step explanation:

you would do 42 divided by 7 which is 6 then subtract 2 from 7 and you would get 5

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Answer:

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Step-by-step explanation:

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3 0
3 years ago
Which are ways to decompose the composite figure into simpler shapes that you have area formulas for? Check all that apply.
Oksanka [162]

Answer:

1st  and second, unless you have already learned area of trapezoids. If you have, add third

Step-by-step explanation:

4 0
3 years ago
Help me solve this problem please
mel-nik [20]
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7 0
2 years ago
Data is collected to compare two different types of batteries. We measure the time to failure of 12 batteries of each type. Batt
-Dominant- [34]

Using the t-distribution, it is found that since the <u>test statistic is greater than the critical value for the right-tailed test</u>, it is found that there is enough evidence to conclude that Battery B outlasts Battery A by more than 2 hours.

At the null hypothesis, it is <u>tested if it does not outlast by more than 2 hours</u>, that is, the subtraction is not more than 2:

H_0: \mu_B - mu_A \leq 2

At the alternative hypothesis, it is <u>tested if it outlasts by more than 2 hours</u>, that is:

H_1: \mu_B - \mu_A > 2

  • The sample means are: \mu_A = 8.65, \mu_B = 11.23
  • The standard deviations for the samples are s_A = s_B = 0.67

Hence, the standard errors are:

s_{Ea} = S_{Eb} = \frac{0.67}{\sqrt{12}} = 0.1934

The distribution of the difference has <u>mean and standard deviation</u> given by:

\overline{x} = \mu_B - \mu_A = 11.23 - 8.65 = 2.58

s = \sqrt{s_{Ea}^2 + s_{Eb}^2} = \sqrt{0.1934^2 + 0.1934^2} = 0.2735

The test statistic is given by:

t = \frac{\overline{x} - \mu}{s}

In which \mu = 2 is the value tested at the hypothesis.

Hence:

t = \frac{\overline{x} - \mu}{s}

t = \frac{2.58 - 2}{0.2735}

t = 2.12

The critical value for a <u>right-tailed test</u>, as we are testing if the subtraction is greater than a value, with a <u>0.05 significance level</u> and 12 + 12 - 2 = <u>22 df</u> is given by t^{\ast} = 1.71

Since the <u>test statistic is greater than the critical value for the right-tailed test</u>, it is found that there is enough evidence to conclude that Battery B outlasts Battery A by more than 2 hours.

A similar problem is given at brainly.com/question/13873630

7 0
3 years ago
a sum of RS 500 is in the form of denominators of RS5 &amp; RS 10..if the total no. of notes is 90 ,find the no. of notes of eac
Katarina [22]
Let rs.5 denominations be x , then rs 10 denominations will be 90-x

then total amount 5x + 10(90-x) which is rs.500

 5x + 10(90-x) = 500

900 - 5x = 500
400 = 5x
therefore x = 80
          therefore no. of rs.5 is 80
no. of rs.10 is 90-x = 90-80 = 10

8 0
3 years ago
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