Answer:
I think its A & B
Two Squares with the same side lengths are always congruent and Two rectangles with the same side lengths are always congruent.
Answer:
m+5nx(9-p)-6-2r
Step-by-step explanation:
here you go
You could actually find the compositions and thus have something to compare. You haven't shared the list of possible answer choices.
(f+g)(x) = 5x - 3 + x + 4 = 6x + 1
(f-g)(x) = 5x - 3 - x - 4 = 4x - 7
(f*g)(x) = (5x-3)((x+4) = 5x^2 + 20x - 3x - 12 = 5x^2 + 17x - 12
There are also the quotient (f/g)(x) and the compositions f(g(x)) and g(f(x)).
WRite them out.
Then you could arbitrarily select x values, such as 2, 10, etc., subst. them into each composition and determine which output is greatest.
Answer:
<I= 15degrees
Step-by-step explanation:
Using the cosine rule formulae;
j² = i²+k²-2i cos <J
j² = 37²+57² - 2(37)(57)cos <141
j² = 1369+ 3249- 4218cos <141
j² = 4618- 4218cos <141
j² = 4618-(-3,278)
j²= 7,896
j = √7,896
j = 88.86inches
Next is to get <I
i² = j²+k²-2jk cos <I
37² = 88.86²+57² - 2(88.86)(57)cos <I
1369 = 7,896.0996+ 3249- 10,130.04cos <I
1369 = 11,145.0996 - 10,130.04cos <I
1369 - 11,145.0996 = - 10,130.04cos <I
-9,776.0996=- 10,130.04cos <I
cos <I =9,776.0996 /10,130.04
cos<I = 0.96506
<I = 15.19
<I= 15degrees
