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Rom4ik [11]
3 years ago
10

Show answer in lowest terms. 25/75+ 25/125=

Mathematics
1 answer:
Anit [1.1K]3 years ago
5 0
Hi Jujub! To find the answer in lowest terms, first you have to find the lowest common denominator. To find this, find the lowest common multiple of 75 and 125, which is 375. Now, to make the common denominator, you have to make equivalent fractions. 375 ÷ 75 = 5, and 5 × 25 = 125. So the new fraction is 125/375.  Now the same thing for 25/125.  375 ÷ 125 = 3, and 3 × 25 is 75. So the new fraction is 75/375.  Now add the new fractions:  
125/375 + 75/375 =  200/375

This answer can be simplified to 8/15.
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Explanation
We start out finding the common difference of the progression:
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a_n=a_1+d(n-1)
\\
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Using the distributive property,
2018=17+29*n-29*1
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8 0
4 years ago
The diameter of a circle is 6 m. Find its area in terms of pi
Pie
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<em>Solution</em><em>,</em>

<em>Diameter</em><em>=</em><em>6</em><em> </em><em>m</em>

<em>Radius=</em><em> </em><em>6</em><em>/</em><em>2</em><em>=</em><em>3</em><em>m</em>

<em>Area </em><em>of </em><em>circle=</em><em> </em><em>pi </em><em>r </em><em>^</em><em>2</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em> </em><em>pi </em><em>*</em><em>(</em><em>3</em><em>)</em><em>^</em><em>2</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em> </em><em>pi*</em><em>9</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>9</em><em> </em><em>pi </em><em>metre^</em><em>2</em>

<em>Hope </em><em>it</em><em> helps</em>

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A

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