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RoseWind [281]
4 years ago
14

Calculate the osmotic pressure of a 5.5M glucose solution at 20 degrees Celsius

Chemistry
1 answer:
NeTakaya4 years ago
5 0

The osmotic pressure is a colligative property which depends upon the number of molecules and not the type of molecules

The relation between osmotic pressure and concentration is

πV = nRT

where

π = Osmotic pressure [ unit atm] = ?

V = volume

n = moles

R = gas constant = 0.0821 L atm / mol K

T = temperature = 20°C = 20 + 273.15 K = 293.15 K

also

Molarity = moles / Volume

So

Molarity = n/V = 5.5 M

Putting values

π = MRT

π = 5.5 X 0.0821 X 293.15 = 132.37 atm

Osmotic pressure of given glucose solution will be 132.37 atm

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Read 2 more answers
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Answer:

a)The mass percentages of nitrogen and phosphorus in the compound is 24.34% and 26.95% respectively.

b) 14.78 grams ammonia is incorporated into 100. g of compound.

Explanation:

a) Ammonium dihydrogen phosphate that is NH_6PO_4.

Molecular mass of ammonium dihydrogen phosphate = M

M = 115 g/mol

Percentage of an element in a compound:

\frac{\text{Number of atoms of element}\times \text{Atomic mass of element}}{\text{molecular mass of element}}\times 100

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\frac{1\times 28 g/mol}{115 g/mol}\times 100=24.34\%

Percentage of phosphorus:

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\%=\frac{17 g/mol}{115 g/mol}\times 100=14.78\%

Amount of ammonia in 100 grams of compound:

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