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LuckyWell [14K]
3 years ago
11

Ammonium dihydrogen phosphate, formed from the reaction of phosphoric acid with ammonia, is used as a crop fertilizer as well as

a component of some fire extinguishers, (a) What are the mass percentages of N and P in the compound? (b) How much ammonia is incorporated into 100. g of compound?
Chemistry
1 answer:
Tema [17]3 years ago
4 0

Answer:

a)The mass percentages of nitrogen and phosphorus in the compound is 24.34% and 26.95% respectively.

b) 14.78 grams ammonia is incorporated into 100. g of compound.

Explanation:

a) Ammonium dihydrogen phosphate that is NH_6PO_4.

Molecular mass of ammonium dihydrogen phosphate = M

M = 115 g/mol

Percentage of an element in a compound:

\frac{\text{Number of atoms of element}\times \text{Atomic mass of element}}{\text{molecular mass of element}}\times 100

Percentage of nitrogen:

\frac{1\times 28 g/mol}{115 g/mol}\times 100=24.34\%

Percentage of phosphorus:

\frac{1\times 31g/mol}{115 g/mol}\times 100=26.95\%

b) Percentage of ammonia in 1 molecule of ammonium dihydrogen phosphate.

Molar mass of ammonia = 17 g/mol

\%=\frac{17 g/mol}{115 g/mol}\times 100=14.78\%

Amount of ammonia in 100 grams of compound:

14.78% of 100 g of ammonium dihydrogen phosphate:

\frac{14.78}{100}\times 100 g=14.78 g

14.78 grams ammonia is incorporated into 100. g of compound.

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if you mixed 72.9g hydrochloric acid(aq) with 150g silver acetate(aq), what would be the limiting reagent?​
horsena [70]

Answer:

                      Silver Acetate would be the Limiting Reagent.

Explanation:

                    The balance chemical equation for the given double displacement reaction is as;

                            HCl + AgC₂H₃O₂ → AgCl + HC₂H₃O₂

Step 1: <u>Calculate Moles of Starting Materials:</u>

Moles of HCl:

                      Moles  =  Mass / M.Mass

                      Moles  =  72.9 g / 36.46

                      Moles =  1.99 moles

Moles of AgC₂H₃O₂:

                      Moles  =  150 g / 166.91 g/mol

                      Moles  =  0.898 moles

Step 2: <u>Find out Limiting reagent as:</u>

According to balance chemical equation.

              1 mole of HCl reacts with  =  1 mole of AgC₂H₃O₂

So,

         1.99 moles of HCl will react with  =  X moles of AgC₂H₃O₂

Solving for X,

                     X =  1.99 mol × 1 mol / 1 mol

                     X =  1.99 mol of AgC₂H₃O₂

Hence, to completely consume 1.99 moles of Hydrochloric acid we will require 1.99 moles of Silver Acetate, But, we are provided with only 0.898 moles of Silver Acetate. This means Silver Acetate will consume first in the reaction therefore, it is the LIMITING REAGENT.

8 0
3 years ago
4Fe + 30₂ ⇒ Fe₂0₃
DaniilM [7]

Answer:

A

The nuber of each one should be same

5 0
2 years ago
What is the relationship between the reactant and yield
solong [7]
Yield is the measured amount of a product obtained from a reaction.

Hope that's helpful
7 0
3 years ago
The path urine takes after it is formed until it leaves the body is the urethra, urinary bladder, and finally the ureter. True F
Vlad1618 [11]

Answer:

False

Explanation:

The urine is produced in the kidneys, each one of the kidneys is connected to a ureter.  The ureter is a tube that propels the excreted urine to the urinary bladder. The urinary bladder is a deposit for the urine, here is collected and stored before disposal. After the urinary bladder, the urine goes through the urethra, which is a tube, to exit the body.

4 0
3 years ago
A lake has been infected by some type of new algae that is unknown. Every single day the amount of surface area that the algae t
FrozenT [24]

Answer:

It takes 86 days take to cover half of the lake

Explanation:

In the day #1, the amount of the algae is X,

In the day #2 is 2X

In the day #3 is 2*2*X = X*2²

...

In the day #n the amount of the algae is X*2^(n-1)

Assuming X = 1m³. In the day 87, the area infected was:

1m³*2^(87-1)

7.74x10²⁵m³ is the total area of the lake

the half of this amount is 3.87x10²⁵m³

The time transcurred is:

3.87x10²⁵m³ = 1m³*2^(n-1)

Multiplying for 5 in each side:

ln (3.87x10²⁵) = ln (2^(n-1))

58.9175 = n-1 * 0.6931

85 = n-1

86 = n

<h3>It takes 86 days take to cover half of the lake</h3>

4 0
3 years ago
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