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3 years ago

How many water molecules are there in the equation CH4 + 202

Chemistry

2 answers:

Svetradugi [14.3K]3 years ago

7 0

How many water molecules are there in the equation CH4 + 202

there are 4 Atomic Atoms im not sure if thats how ur supposed to answer it

Otrada [13]3 years ago

5 0

None, unless a single displacement reaction takes place. There is 4 hydrogen and 4 oxygens which could potentially make 2 water molecules (H2O). I’m not entirely sure though.

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Calculate the pZn of a solution prepared by mixing 25.0 mL of 0.0100 M EDTA with 50.0 mL of 0.00500 M Zn2 . Assume that both the

egoroff_w [7]

Answer:

$\mathbf{pZn ^{2+} =8.8569 }$

Explanation:

Using the approach of Henderson-HasselBalch equation, we have :

$pH = pKa[NH^+_4] + log \dfrac{[NH_3]}{[NH_4^+]}$

where;

the pKa of $NH^+_4$ = 9.26

concentration of $NH_3$ = 0.100 M

concentration of $NH_4Cl$ = 0.176 M

∴

the pH of the buffered solution is :

$pH = 9.26 + log \dfrac{[0.100]}{[0.176]}$

$pH = 9.26 + log (0.5682)$

$pH = 9.26 +(-0.2455)$

$pH =9.02$

The Chemical equation for the reaction of $Zn ^{2+}$ and EDTA is :

$Zn^{2+}_{(aq)} + Y^{4-}_{(aq)} \iff ZnY^{2-} _{(aq)}$

Here;

$Y^{4-}_{(aq)}$ denotes the fully deprotonated form of the EDTA

The formation constant $K_f$ of the equation for the reaction can be represented as:

$K_f = \dfrac{[ZnY^{2-}]}{[Zn^{2+} ][Y^{4-}]}$ ----- (1)

The logarithm of the formation constant of Zn - EDTA complex = 16.5

$K_f$ = $10^{16.5}$

$K_f$ = $3.16 \times 10^{16}$

Since the formation constant in the above equation signifies that the EDTA is present in $Y^{4-}$ ,

Then:

$\alpha _{Y^{4-} }= \dfrac{Y^{4-}}{C_{EDTA}}$

${Y^{4-}}= \alpha_ {Y^{4-}} \times {C_{EDTA}}$

From (1)

$K_f = \dfrac{[ZnY^{2-}]}{[Zn^{2+} ][Y^{4-}]}$

$K_f = \dfrac{[ZnY^{2-}]}{[Zn^{2+} ] \ \ \alpha_ {Y^{4-}} \times {C_{EDTA}}}$

∴

$K_f' = K_f \times \alpha _Y{^4-} = \dfrac{[ZnY^{2-}]}{[Zn^{2+} ] \ C_{EDTA} }$

where;

$K_f'$ = conditional formation constant

$\alpha _Y{^4-}$ = the fraction of EDTA that exit in the form of the presences of the 4 charges .

So at equivalence point :

all the $Zn^{2+}$ initially in titrand is now present in $ZnY^{2-}$

$K_f' = K_f \times \alpha _Y{^4-}$

Obtaining the data for the value of $\alpha _Y{^4-}$ at the reference table:

$\alpha _Y{^4-}$ = $5.4 \times 10^{-12}$

∴

$K_f' = 3.16 \times 10^{16} \times 5.4 \times 10^{-2}$

$K_f' = 1.7064 \times 10^{15}$

To calculate the moles of EDTA , $Zn^{2+}$ , $ZnY^{2-}$ ; we have:

moles of EDTA = 0.0100 M × 0.025 L

moles of EDTA = $2.5 \times 10^{-4} \ mole$

moles of $Zn^{2+}$ = 0.00500 M × 0.050 L

moles of $Zn^{2+}$ = $2.5 \times 10^{-4} \ mole$

moles of $ZnY^{2-}$ = $\dfrac{initial \ mole}{total \ volume}$

moles of $ZnY^{2-}$ = $\dfrac{2.5 \times 10^{-4}}{ 0.025 + 0.050 }$

moles of $ZnY^{2-}$ = $\dfrac{2.5 \times 10^{-4}}{ 0.075 }$

moles of $ZnY^{2-}$ = 0.0033333 M

Recall that:

$K_f' = K_f \times \alpha _Y{^4-} = \dfrac{[ZnY^{2-}]}{[Zn^{2+} ] \ C_{EDTA} }$

$K_f' = \dfrac{[ZnY^{2-}]}{[Zn^{2+} ] \ C_{EDTA} }$

Assume Q² is the amount of complex dissociated in $ZnY^{2-}$

$ZnY^{2-} \iff Zn^{2+} + C_{EDTA}$

i.e $Q^2 = Zn^{2+} + C_{EDTA}$

$1.707 \times 10^{15}= \dfrac{0.0033333}{Q}$

$Q= \dfrac{0.0033333}{1.707 \times 10^{15}}$

$Q^2= \dfrac{0.0033333}{1.707 \times 10^{15}}$

$Q^2= 1.9527 \times 10^{-18}$

$Q= \sqrt{1.9527 \times 10^{-18}}$

Q = $1.397 \times 10^{-9}$ M

$[Zn^{2+}]= 1.39 \times 10^{-9} \ M$

∴

$pZn ^{2+} =- log [Zn^{2+}]$

$pZn ^{2+} = - log (1.39 \times 10^{-9} ) \ M$

$\mathbf{pZn ^{2+} =8.8569 }$

4 0

3 years ago

How many moles of KOH are there in 27.5 mL of 0.250 M KOH?

zaharov [31]

Answer:

6.88 × 10^-3mol

Explanation:

Molarity = number of moles (n) ÷ volume (V)

According to this question, there in 27.5 mL of 0.250 M KOH, the number of moles of KOH can, therefore, be calculated as follows:

number of moles = molarity × volume

Volume of KOH = 27.5mL = 27.5/1000

= 0.0275L

n = 0.0275 × 0.250

n = 0.006875 mol

n = 6.88 × 10^-3mol

7 0

3 years ago

In baking biscuits and other quick breads, the

stiv31 [10]

Answer:

chemical

Explanation:

The trapped carbon dioxide makes the dough rise, and the alcohol evaporates during the baking process. This is an irreversible chemical change, because by consuming the sugar, the yeast has created new substances

6 0

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Nataliya [291]

Answer: Since all sodium atoms have 11 protons, this one has 11 protons. This tells us that it also has 11 electrons. Since the mass number is 23, we know that the sum of protons and neutrons in the nucleus must equal 23.

So the answer is : Mass number = 23

Explanation:

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mamaluj [8]

Answer:

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