Use format y = mx + b
-15x + 5y = 20
-15x + 15x + 5y = 20 + 15x
5y = 20 + 15x
y = (20 + 15x)/5
y = 4 + 3x
y = 3x + 4
m is the slope, so 3 is the answer
Answer:
The first expression can be rewritten as
35 {b}^{2} = 5 \times 7 \times {b}^{2}35b
2
=5×7×b
2
The second expression is rewritten as
15 {b}^{3} = 3 \times 5 {b}^{3}15b
3
=3×5b
3
The third expression is
5b = 5 \times b5b=5×b
The greatest common factor is the product of the least powers of the common factors.
Answer:
4 quarters
20 Nickels
60 dimes
Step-by-step explanation:
4Q x 5 = 20N
20N x 3 = 60D
add them in to dollars you get one dollar each from the nickels and quarters and 6 dollars from the dimes.
Answer:
The experimental probability of landing on heads is 0.3
Step-by-step explanation:
We are given the following in the question:
Number of heads = 30
Number of tails = 70
Talia said the probability of getting heads is 
.
She evaluated the wrong probability.
She did not considered total number of trials in the experiment.
Formula for probability:
Probability of heads =
The experimental probability of landing on heads is 0.3
Answer:
The best conclusion that can be made based on the data on the dot plot is:
The mean difference is not significant because the re-randomization show that it is within the range of what could happen by chance.
Step-by-step explanation:
Randomization is the standard used to compare the observational study and balance the factors between the treatment groups and eliminate the variables' influence. Some studies analyze that the treatment in the randomization calculates the appropriate number of the subjects as the treatment to memorize is 8.9, and the treatment for the B is 12.1 words.
The mean difference is not significant because the re-randomization shows that it is within the range of what could happen by chance.
The treatment group using technique A reported a mean of 8.9 words.
The treatment group using technique B reported a mean of 12.1 words.
After the data are re-randomized, the differences of means are shown in the dot plot.
The result is significant because the re-randomization show that it is outside the range. The best conclusion that can be made based on the data on the dot plot is:
The mean difference is not significant because the re-randomization show that it is within the range of what could happen by chance.
