Answer:

Step-by-step explanation:
<u>Given Data:</u>
Base area =
= 108 in.²
Volume = V = 729 in.³
<u>Required:</u>
Height = h = ?
<u>Formula:</u>

<u>Solution:</u>
For h, rearranging formula:
![\displaystyle h = \frac{V}{A_{B}} \\\\h =\frac{729 \ in.^3}{108 \ in.^2} \\\\h = 6.75 \ in.\\\\\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20h%20%3D%20%5Cfrac%7BV%7D%7BA_%7BB%7D%7D%20%5C%5C%5C%5Ch%20%3D%5Cfrac%7B729%20%5C%20in.%5E3%7D%7B108%20%5C%20in.%5E2%7D%20%5C%5C%5C%5Ch%20%3D%206.75%20%5C%20in.%5C%5C%5C%5C%5Crule%5B225%5D%7B225%7D%7B2%7D)
Let's simplify step-by-step.
2/
5
y−4+7−
9
/10
y
=
2
/5
y+−4+7+
−9
/10
y
Combine Like Terms: =
2
/5
y+−4+7+
−9
/10
y
(2
/5
y+
−9
/10
y)+(−4+7)
=
−1
/2
y+3
Answer: =
−1
/2
y+3
Hope I could help! :)
Answer:

Step-by-step explanation:

Let's convert the mixed number to an important fraction.
-1 1/6 = -7/6
Now multiply:

-Chetan K
Probability is calculated by comparing the odds to a certain event occurring to the number of possible events.
P=

For example, take a six-sided dice number 1-6 on each side. The probability of rolling a 4 would be1 in 6 or 1/6. This is because of the six possible outcomes, rolling a 4 is only one of them.
P(4)=1/6
Now take the same dice. The probability of rolling an even number is 3/6. To see why, lets look at the total possible outcomes:
1
23
45
6
Of the 6 possibilities, 3 are even numbers.
P(even)=3/6 or 1/2
Answer:
tanΘ = - 
Step-by-step explanation:
Using the trigonometric identity
tan²Θ + 1 = sec²Θ, thus
tan²Θ + 1 = (
)² =
( subtract 1 from both sides )
tan²Θ =
( take the square root of both sides )
tanΘ = ± 
Since 270 < Θ < 360 , that is the fourth quadrant where tan Θ < 0, thus
tanΘ = - 