Answer:
The answer is below
Step-by-step explanation:
Select the correct answer from each drop-down menu. Simplify the given polynomial and use it to complete the statement.
(-5x² - 2x + 4) + (8x² - x - 1) + (x + 2)(x - 5)
.The polynomial simplifies to an expression that is a____
A.quadratic
B.liner
C.constany
A.trinomial
B.binomial
C.monomial
with a degree of____
A.1
B.2
C.0
Solution:
A polynomial is an expression involving operations of addition, subtraction, multiplication, exponents which consists of variables and their coefficient. A trinomial is a polynomial consisting of three terms, while a binomial consist of two terms and a monomial consist of one term.
The degree of a polynomial is the highest degree of any of the terms of the polynomial. If it has a degree of 0 it is a constant, a degree of 1 it is linear while for a degree of 2 it is quadratic.
(-5x² - 2x + 4) + (8x² - x - 1) + (x + 2)(x - 5)
= (-5x² - 2x + 4) + (8x² - x - 1) + (x² -5x + 2x - 10)
= (-5x² - 2x + 4) + (8x² - x - 1) + (x² - 3x - 10)
= (-5x² + 8x² + x² - 2x - x - 3x + 4 - 1 - 10)
= 4x² - 6x - 7
Therefore:
.The polynomial simplifies to an expression that is a quadratic trinomial of degree 2.
Answer:
temp after 7 minutes is 135°
temp after 't' minutes: y = 65 + 10t
Step-by-step explanation:
Answer:43
Step-by-step explanation:
bc it is
The answer is B any number becomes positive when looking for absolute value..
Brailiest is always appreciated
Answer:
Part 1) ![x=14\sqrt{2}\ units](https://tex.z-dn.net/?f=x%3D14%5Csqrt%7B2%7D%5C%20units)
Part 2) ![y=14\ units](https://tex.z-dn.net/?f=y%3D14%5C%20units)
Part 3) ![z=14\sqrt{3}\ units](https://tex.z-dn.net/?f=z%3D14%5Csqrt%7B3%7D%5C%20units)
Step-by-step explanation:
see the attached figure with letters to better understand the problem
step 1
In the right triangle ABC
we know that
The triangle ABC is a ![45^o-90^o-45^o](https://tex.z-dn.net/?f=45%5Eo-90%5Eo-45%5Eo)
so
Is an isosceles right triangle
The legs are equal
therefore
AC=AB
![x=14\sqrt{2}\ units](https://tex.z-dn.net/?f=x%3D14%5Csqrt%7B2%7D%5C%20units)
step 2
Find the length side BC
Applying the Pythagorean Theorem]
![BC^2=AB^2+AC^2](https://tex.z-dn.net/?f=BC%5E2%3DAB%5E2%2BAC%5E2)
![BC^2=(14\sqrt{2})^2+(14\sqrt{2})^2](https://tex.z-dn.net/?f=BC%5E2%3D%2814%5Csqrt%7B2%7D%29%5E2%2B%2814%5Csqrt%7B2%7D%29%5E2)
![BC^2=784\\BC=28\ units](https://tex.z-dn.net/?f=BC%5E2%3D784%5C%5CBC%3D28%5C%20units)
step 3
Find the value of y
In the right triangle BCD
----> by SOH (opposite side divided by the hypotenuse)
![sin(30^o)=\frac{y}{28}](https://tex.z-dn.net/?f=sin%2830%5Eo%29%3D%5Cfrac%7By%7D%7B28%7D)
Remember that
![sin(30^o)=\frac{1}{2}](https://tex.z-dn.net/?f=sin%2830%5Eo%29%3D%5Cfrac%7B1%7D%7B2%7D)
so
![\frac{y}{28}=\frac{1}{2}\\\\y=14\ units](https://tex.z-dn.net/?f=%5Cfrac%7By%7D%7B28%7D%3D%5Cfrac%7B1%7D%7B2%7D%5C%5C%5C%5Cy%3D14%5C%20units)
step 4
Find the value of z
In the right triangle BCD
----> by CAH (adjacent side divided by the hypotenuse)
![cos(30^o)=\frac{z}{28}](https://tex.z-dn.net/?f=cos%2830%5Eo%29%3D%5Cfrac%7Bz%7D%7B28%7D)
Remember that
![cos(30^o)=\frac{\sqrt{3}}{2}](https://tex.z-dn.net/?f=cos%2830%5Eo%29%3D%5Cfrac%7B%5Csqrt%7B3%7D%7D%7B2%7D)
so
![\frac{z}{28}=\frac{\sqrt{3}}{2}\\z=14\sqrt{3}\ units](https://tex.z-dn.net/?f=%5Cfrac%7Bz%7D%7B28%7D%3D%5Cfrac%7B%5Csqrt%7B3%7D%7D%7B2%7D%5C%5Cz%3D14%5Csqrt%7B3%7D%5C%20units)