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ololo11 [35]
2 years ago
10

3. Lines 1, 2 and 3 are graphed on the coordinate plane below.

Mathematics
1 answer:
Alenkinab [10]2 years ago
8 0

Answer:

I think it is d

Step-by-step explanation:

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Harlamova29_29 [7]

Answer: d=12

Step-by-step explanation:

\displaystyle\\\frac{3d-2}{8} =-d+16\frac{1}{4} \\\\\frac{3d-2}{8} =-d+\frac{16*4+1}{4} \\\\\frac{3d-2}{8} =-d+\frac{64+1}{4} \\\\\frac{3d-2}{8} =-d+\frac{65}{4}

Multiply both parts of the equation by 8:

\displaystyle\\3d-2=(-d+\frac{65}{4} )(8)\\\\3d-2=-8d+65*2\\\\3d-2=-8d+130\\\\3d-2+2=-8d+130+2\\\\3d=-8d+132\\\\3d+8d=-8d+132+8d\\\\11d=132\\

Divide both parts of the equation by 11:

d=12

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1 year ago
In the diagram of circle R, m∠FGH is 50°. What is m? 130° 230° 260° 310°
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we know that

The measurement of the exterior angle is the semi-difference of the arcs which comprises

In this problem

∠FGH is the exterior angle

∠FGH=50\°

∠FGH=\frac{1}{2}(arc\ FEH-arc\ FH)

50\°=\frac{1}{2}(arc\ FEH-arc\ FH)

100\°=(arc\ FEH-arc\ FH)  -----> equation A

arc\ FEH+arc\ FH=360\°

arc\ FH=360\°-arc\ FEH --------> equation B

Substitute equation B in equation A

100\°=(arc\ FEH-[360\°-arc\ FEH])

100\°=2arc\ FEH-360\°

2arc\ FEH=360\°+100\°

arc\ FEH=230\°

therefore

<u>The answer is</u>

The measure of arc FEH is equal to 230\°

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