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Zanzabum
3 years ago
5

Will give Brainliest! if right!

Mathematics
2 answers:
alexira [117]3 years ago
7 0
The answer is c. 240. Hope I helped. Have a good day!
Firlakuza [10]3 years ago
6 0
I would like to say D) 300 if im understanding the question correctly
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If one factor of x2 + 2x - 24 is (x+6), what is the other factor?
steposvetlana [31]

Answer:

( x - 4)

Step-by-step explanation:

x² + 2x - 24

From here, you must find the two factors of -24 (the first and third terms' coefficients multiplied together) that add up to 2 (the middle terms coefficient)

( x - 4) ( x + 6)

4 0
3 years ago
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What is the volumenof the sphere rounded to the nearest hunderths?​
Kryger [21]
9202.77 it should be
7 0
3 years ago
The ratio of men to women working for a company is 3 to 5 . if there are 140 women working for the company, what is the total nu
Naddika [18.5K]

Ratio of men : women = 3 : 5

-

<u>Find total parts:</u>

3 + 5 = 8

-

<u>Find 1 part:</u>

5 parts = 140

1 part = 140 ÷ 5 = 28

-

<u>Find 8 parts (total):</u>

8 parts = 28 x 8 = 224

-

Answer: There are 224 employees

4 0
3 years ago
Use the Newton-Raphson method to find the root of the equation f(x) = In(3x) + 5x2, using an initial guess of x = 0.5 and a stop
xxMikexx [17]

Answer with explanation:

The equation which we have to solve by Newton-Raphson Method is,

 f(x)=log (3 x) +5 x²

f'(x)=\frac{1}{3x}+10 x

Initial Guess =0.5

Formula to find Iteration by Newton-Raphson method

  x_{n+1}=x_{n}-\frac{f(x_{n})}{f'(x_{n})}\\\\x_{1}=x_{0}-\frac{f(x_{0})}{f'(x_{0})}\\\\ x_{1}=0.5-\frac{\log(1.5)+1.25}{\frac{1}{1.5}+10 \times 0.5}\\\\x_{1}=0.5- \frac{0.1760+1.25}{0.67+5}\\\\x_{1}=0.5-\frac{1.426}{5.67}\\\\x_{1}=0.5-0.25149\\\\x_{1}=0.248

x_{2}=0.248-\frac{\log(0.744)+0.30752}{\frac{1}{0.744}+10 \times 0.248}\\\\x_{2}=0.248- \frac{-0.128+0.30752}{1.35+2.48}\\\\x_{2}=0.248-\frac{0.17952}{3.83}\\\\x_{2}=0.248-0.0468\\\\x_{2}=0.2012

x_{3}=0.2012-\frac{\log(0.6036)+0.2024072}{\frac{1}{0.6036}+10 \times 0.2012}\\\\x_{3}=0.2012- \frac{-0.2192+0.2025}{1.6567+2.012}\\\\x_{3}=0.2012-\frac{-0.0167}{3.6687}\\\\x_{3}=0.2012+0.0045\\\\x_{3}=0.2057

x_{4}=0.2057-\frac{\log(0.6171)+0.21156}{\frac{1}{0.6171}+10 \times 0.2057}\\\\x_{4}=0.2057- \frac{-0.2096+0.21156}{1.6204+2.057}\\\\x_{4}=0.2057-\frac{0.0019}{3.6774}\\\\x_{4}=0.2057-0.0005\\\\x_{4}=0.2052

So, root of the equation =0.205 (Approx)

Approximate relative error

                =\frac{\text{Actual value}}{\text{Given Value}}\\\\=\frac{0.205}{0.5}\\\\=0.41

 Approximate relative error in terms of Percentage

   =0.41 × 100

   = 41 %

7 0
3 years ago
PLEASE HELP ASAP! BRAINLIEST AND 5 STARS TO BEST/CORRECT RESPONSE(S).
Lunna [17]

Answer:

b). (0, 4)

if you need an explanation, comment, and I will put one in for you :)

7 0
2 years ago
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