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choli [55]
3 years ago
14

stretch your thinking write three different addition equations that have the sum of 834 and require at least one new group​

Mathematics
2 answers:
777dan777 [17]3 years ago
5 0

Answer:

the answer for this question 1200

Step-by-step explanation:

Cerrena [4.2K]3 years ago
4 0
200+600+34
800+30+4
500+300+34
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salantis [7]
The answer is 153.86:
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3 years ago
Please help thanks :)
kykrilka [37]
Question 1:

Multiply both sides of the proportion by 35.

You get.

7(x-1) = 4x+2

7x-7 = 4x+2

Now, add both sides by 7 and subtract both sides by 4x

3x = 9

Divide both sides by 3

x=3

Question 2:

Multiply both the numerator and the denominator of \frac{x+1}{x+3} by 3.

We want to multiply it by 3 so that the +1 and +3 become +3 and +9. +3 and +9 have a difference of 6, just like 15 and 21, which is what we want.

\frac{3x+3}{3x+9} = \frac{15}{21}

Set the numerator equal to the numerator and the denominator equal to the denominator.

3x+3 = 15

3x+9 = 21

If you solve both of these, you get x=4 for both.

That's your answer.

Hope this helps! :)
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4 years ago
What is the difference between subject Based Curriculum and objective Based Curriculum​
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Answer:

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Tuesday because the 7 days of the week

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