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3 years ago

stretch your thinking write three different addition equations that have the sum of 834 and require at least one new group

Mathematics

2 answers:

777dan777 [17]3 years ago

5 0

Answer:

the answer for this question 1200

Step-by-step explanation:

Cerrena [4.2K]3 years ago

4 0

200+600+34
800+30+4
500+300+34

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Find the value of logarithm log(4)1

MissTica

If 4^x=1, whats x?
X=0
So log(4)1=0

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4 years ago

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||3x-4|-5|>1<br> Please Help Me!<br> 20 points!

faltersainse [42]

Answer:

4(3 −1)−5=75

Step-by-step explanation:

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3 years ago

Two faulty machines, M1 and M2, are repeatedly run synchronously in parallel (i.e., both machines execute one run, then both exe

leonid [27]

The event that either M1 or M2 fails has probability

$P(M_1\text{ fails or }M_2\text{ fails})=P(M_1\text{ fails})+P(M_2\text{ fails})-P(M_1\text{ and }M_2\text{ both fail})$

by the addition rule. Failure events are independent, so

$P(M_1\text{ and }M_2\text{ both fail})=P(M_1\text{ fails})P(M_2\text{ fails})$

so that

$P(M_1\text{ fails or }M_2\text{ fails})=p_1+p_2-p_1p_2$

Denote this probability by $p$ . Then $X$ follows a geometric distribution with this parameter $p$ and has density

$P(X=x)=\begin{cases}(1-p)^{x-1}p&\text{for }x\ge1\\0&\text{otherwise}\end{cases}$

The expectation is $\dfrac1p=\dfrac1{p_1+p_2-p_1p_2}$ .

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4 years ago

The area of a trapezium is 800 cm2

svlad2 [7]

Answer:

The distance between the parallel sides is 20cm.

Step-by-step explanation:

Area of a trapezoid:

$A=\frac{a+b}{2}\times h$

where a and b are the 2 bases, and h is the height. The value we're trying to find here is the height.

3 of the 4 variables in this equation are already given:

A = 800

a = 48

b = 32

Just plug those in and solve for h:

$\rightarrow 800=\frac{48+32}{2}\times h\\\rightarrow 800=\frac{80}{2}\times h\\\rightarrow 800=40\times h\\\rightarrow 800\div40=h\\\rightarrow h=20$

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3 years ago

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If PQ=21 cm and QR=5cm, then what are the possible lengths for PR so that line PQ, line QR, and line PR can form a triangle? exp

Klio2033 [76]

We know that PQ is 21 cm and QR is 5 cm. There are only 2 possible answer for this and you use only one formula. It's called the Pythagorean theorem.

The first possible is this. If the hypotenuse(the longest side of a triangle) is PR, we do:
a² + b² = c² ←Fill in the numbers
21² + 5² = c²
441 + 25 = c²
466 = c²
√466 = 21.12 cm←Possible length

The second possible is this:
5² + b² = 21²
25 + b² = 441
b² = 441 - 25
b² = 416
√416 = 20.4←Another possible answer

8 0

4 years ago

stretch your thinking write three different addition equations that have the sum of 834 and require at least one new group​

stretch your thinking write three different addition equations that have the sum of 834 and require at least one new group