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3 years ago

stretch your thinking write three different addition equations that have the sum of 834 and require at least one new group

Mathematics

2 answers:

777dan777 [17]3 years ago

5 0

Answer:

the answer for this question 1200

Step-by-step explanation:

Cerrena [4.2K]3 years ago

4 0

200+600+34
800+30+4
500+300+34

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Three cell phones towers can be modeled by the points X(6,0), Y(8,4), and Z(3,9). Determine the location of another cell phone t

Marat540 [252]

Answer:

The location of the new cell phone tower is $(h,k) = (3,4)$ , and the equation of the circle is $x^{2}+y^{2} -6\cdot x - 8\cdot y = 0$ .

Step-by-step explanation:

The location of the cell phone tower coincides with the location of a circunference passing through the three cell phone towers. By Analytical Geometry, the equation of the circle is represented by the following general formula:

$x^{2} + y^{2}+A\cdot x + B\cdot y +C = 0$ (1)

Where:

$x$ - Independent variable.

$y$ - Dependent variable.

$A$ , $B$ , $C$ - Circunference constants.

Given the number of variable, we need the location of three distinct points:

$(x_{1},y_{1}) = (6,0)$

$36 +6\cdot A + C = 0$

$(x_{2},y_{2}) = (8,4)$

$80 + 8\cdot A + 4\cdot B + C = 0$

$(x_{3},y_{3}) = (3,9)$

$90 + 3\cdot A + 9\cdot B + C = 0$

Then, we have the following system of linear equations:

$6\cdot A + C = -36$ (2)

$8\cdot A +4\cdot B + C = -80$ (3)

$3\cdot A + 9\cdot B + C = -90$ (4)

The solution of this system is:

$A = -6$ , $B = -8$ , $C = 0$

By comparing the general form with the standard form of the equation of the circunference is:

$A = -2\cdot h$ (5)

$B = -2\cdot k$ (6)

$C = h^{2}+k^{2}-r^{2}$ (7)

Where:

$h$ , $k$ - Coordinates of the center of the circle.

$r$ - Radius of the circle.

If we know that $A = -6$ , $B = -8$ and $C = 0$ , then coordinates of the center of the circle and its radius are, respectively:

$h = -\frac{A}{2}$

$k = -\frac{B}{2}$

$r = \sqrt{h^{2}+k^{2}-C}$

$h = 3$ , $k = 4$ , $r = 5$

The location of the new cell phone tower is $(h,k) = (3,4)$ , and the equation of the circle is $x^{2}+y^{2} -6\cdot x - 8\cdot y = 0$ .

3 0

3 years ago

I NEED HELP ON QUESTION B AND C ASAP.

ipn [44]

Answer:

See below

Step-by-step explanation:

Assumed the dimensions of the top and bottom parts are identical.

Since the cylindrical part has total height of 1.8 cm and the hemisphere volume is transferred to bottom part and the cone part is still full, the value of h is the difference of the total height of cylinder and full part of the top section of cylinder:

h = 1.8 cm - 0.3 cm = 1.5 cm

Find the volume of sand in the bottom part. It consists of a hemisphere and a cylinder of 1.5 cm height.

V(cylinder) = πr²h = 3.14*(2.6/2)²*1.5 ≈ 7.96 cm³
V(hemisphere) = 2/3πr³ = 2/3*3.14*(2.6/2)³ ≈ 4.6 cm³

<u>Total sand in the bottom part:</u>

7.96 + 4.6 = 12.56 cm³

<u>Time taken:</u>

12.56 / 0.05 = 251.2 seconds = 4 min 11.2 seconds

8 0

2 years ago

What is the square root of 36x to the fourth power?

-BARSIC- [3]

$\sqrt{36x^4}=\sqrt{36}\cdot\sqrt{x^4}=\sqrt{6^2}\cdot\sqrt{(x^2)^2}=6\cdot x^2=\boxed{6x^2}$

8 0

3 years ago

6(4x+5)=3(x+8)+3 round to the nearest hundredth

Naddik [55]

0.14
There is supposed to be a bar on the top like a line but I couldn’t put it here so u can put it urself if ur writing it on paper

5 0

3 years ago

The Kuroshio Sea tank is 27m long, 35m wide and 10m deep. What is the volume of the tank? Show your

umka21 [38]

The volume of Kuroshio Sea rank is 9450 cubic meters, if the sea tank is 27m long, 35m wide and 10m deep.

Step-by-step explanation:

The given is,

Kuroshio Sea tank is 27m long, 35m wide and 10m deep.

Step:1

Sea tank looks like a rectangular prism,

Formula to calculate the volume of rectangular prism,

$Volume, V =whl$ .............................(1)

Where, w - Width of the rectangular prism

h - Height or depth of the rectangular prism

l - Length of the rectangular prism

From given,

w = 35 meters

l = 27 meters

h = 10 meters

Equation (1) becomes,

$V = (35)(10)(27)$

$= (945)(10)$

$=9450$

Volume of the sea tank, V = 9450 Cubic meters

Result:

The volume of Kuroshio Sea rank is 9450 cubic meters, if the sea tank is 27m long, 35m wide and 10m deep.

3 0

4 years ago

stretch your thinking write three different addition equations that have the sum of 834 and require at least one new group​

stretch your thinking write three different addition equations that have the sum of 834 and require at least one new group