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andreev551 [17]

2 years ago

11

A school has a goal of getting at least 2000 boxtops.They have 8 days left to get it. At least how many do they need to collect

each day to meet or exceed their goal?

2 answers:

vova2212 [387]2 years ago

5 0

They need to get at least 250 boxtops each day to meet or exceed the goal. Hope this helps!

777dan777 [17]2 years ago

4 0

The answer is 250 box tops

To check your answer you can do:

250x8

Which equals : 2000 boxtops

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Starting at home, Luis traveled uphill to the gift store for 50 minutes at just 6 mph. He then traveled back home along the same

Georgia [21]

Answer:

Therefore his average speed for the entire trip is 8 mph.

Step-by-step explanation:

Given, In 50 minutes Luis traveled uphill to gift store at 6 mph.

6 mph means in 1 h= 60 minutes Luis can covered 6 mile.

In 1 minutes Luis can covered $\frac{6}{60}$ mile.

In 50 minutes Luis can covered $\frac{6\times 50}{60}$ mile

= 5 mile

Again when he come back at home, the speed was 12 mph.

12 mph means in 1 h= 60 minutes Luis can covered 12 mile.

Therefore he traveled 12 mile in 60 minutes

He traveled 1 mile in $\frac{60}{12}$ minutes.

He traveled 5 mile in $\frac{60\times 5}{12}$ minutes

= 25 minutes.

Total distance for the entire trip is =(5+5) mile=10 mile

Total time for the entire trip is = (50+25) minutes = 75 minutes

$\textrm{Average speed}=\frac{\textrm{Total distance}}{\Textrm {total time}}$

$=\frac{10}{75}$ m/min

$=\frac{10\times 60}{75}$ mph

= 8 mph

Therefore his average speed for the entire trip is 8 mph.

4 0

3 years ago

Help me on this i will give people 20pts

levacccp [35]

No. 1/4 of an hour is 15 minutes..
15 minutes read every day for 15 days is 225 minutes, which is less than 500

7 0

3 years ago

Read 2 more answers

Last one please explain and give answer

nlexa [21]

4p - 5 (p + 6 )

4p - 5p - 30

-p -30

this is the answer.

hope it helps.

4 0

3 years ago

Trains headed for destination A arrive at the train station at 15-minute intervals tarting at 7am, where as trains headed for de

grandymaker [24]

Answer: a.) 2/3 ; b.) 7/12

Step-by-step explanation:

Given the following details :

Destination A trains arrives at station at 15 minutes interval starting from 7am

Destination B trains arrives at station at 15 minutes interval starting from 7.05am

A.) if a passenger arrives at station uniformly between 7am and 8am and gets on first train. What proportion of time does the passenger leave from destination A?

To leave for destination A. The passenger has to arrive before train to A departs and after train to B leaves.

Train to B leaves, starting at at 7.05 a.m and at interval of 15 minutes

Train to A leaves at 7.00 am and at interval of 15 minutes.

Therefore,

(Train B departs - train A arrives) (between 7 to 8am)

(7.05 - 7.15) + (7.20 - 7.30) + (7.35 - 7.45) + (7.50 - 8.00) = 40 minutes

Total time = 7.00 - 8.00 = 60 minutes

(40 ÷ 60) = 2/3 or 0.667

B.) If passenger arrives uniformly between 7.10am - 8:10am

(7.10 - 7.15) + (7.20 - 7.30) + (7.35 - 7.45) + (7.50 - 8)

5 + 10 + 10 + 10 = 35

35/60 = 7/12 or 0.583

8 0

3 years ago

I WILL GIVE BRAINLIEST HELP PLEASEEEE HELP PLEASEEE

Lady bird [3.3K]

Answer:

-39

Step-by-step explanation:

$\left(-3\right)^3-\sqrt[3]{27}-4^3\left(\sqrt[3]{64}-\left(2\right)\left(2\right)\right)-\frac{\left(3\right)^3\left(2\right)}{6}$

$-27-3-64\left(4-4\right)-\frac{54}{6}$

$-27-3-\frac{54}{6}$

$-27-3-9$

Which gives us -39.

5 0

3 years ago