Let a=price of adult ticket
let c=price of a child's ticket
start out by writing the following system of equations:
3a+4c=132
2a+3c=94
then, multiply the first equation by 2, and the second equation by 3 to get the following system of equations:
6a+8c=264
6a+9c=282
subtract the like terms to get the following equation:
-c=-18
divide both sides by -1 to get rid of the negative to get the price of a child's ticket to be $18. to find the price of an adult ticket, pick one of the original equations to substitute the 18 in for c to find a. for example:
2a+3c=94
2a+3(18)=94
2a+54=94
-54 -54
2a=40
2 2
a=20
or if you decide to use the other equation:
3a+4c=132
3a+4(18)=132
3a+72=132
-72 -72
3a=60
3 3
a=20
either way, you still get an adults ticket to be $20 and a child's ticket to be $18.
<u>Please</u><u> </u><u>put</u><u> </u><u>a</u><u> </u><u>picture</u><u> </u><u>next</u><u> </u><u>time</u><u> </u><u>:</u><u>)</u>
3*3-5*+834556665334567776543
Answer:
Its 6 cookies per day
Step-by-step explanation:
12/2=6 6 cookies per day
(√3n)-23=16
Put all of the numbers without a variable on the right side of the equation
(√3n)=39
Simplify
<span>1.732051n</span>=<span>39
</span>
Divide 39 by 1.732051
n=<span>22.516658
Round
n=22.5</span>