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Gala2k [10]
3 years ago
10

780 56° (100° (x + 48)°

Mathematics
1 answer:
Marta_Voda [28]3 years ago
4 0

Answer:

The Question is Incomplete still What i understood I let you Explain.

x = 78°  

Step-by-step explanation:

Let

m∠ A = 78°

m∠ B = 56°

m∠ C = 100°

m∠ D = (x + 48)°

Be angles of Quadrilateral.

To Find:

x = ?

Solution:

Property of a Quadrilateral sum of the measures of the angle is 360°.

∴ m∠ A + m∠ B + m∠ C + m∠ D =  360°

Substituting above given values we get

∴ 78° +56° + 100° + ( x + 48° ) = 360°

∴ x + 282° = 360°

∴ x = 360° - 282°

∴ x = 78°     ........... which the required answer

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420 (lol)

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If melba rode her bike 7/8 miles in 1/4hour. what is the unit rate in miles per hour
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3.5 miles per hour. 7/8 (.875) divided by 1/4 (.25)  equals 3.5. Hope this helps!
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What the answer to this "difficult" math equation?
Ksju [112]

Answer:

1 + 1 + 2 + 2 + 3 + 3 + 4 + 4 + 5 + 5 + 6 + 6 + 7 + 7 + 8 + 8 + 9 + 9 + 10 + 10 - 90 = 20

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Someone help please!!!!
MAXImum [283]

Answer:

60cm²

Step-by-step explanation:

as the green and blue box are squares they will have the same sides, length.

so all the sides in the green and blue squares are 3

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4 0
2 years ago
Find the area of the shaded region. Round the nearest hundredth if necessary. YZ=14.2m
andreyandreev [35.5K]

Complete Question

The complete question is shown on the first uploaded image

Answer:

1

   A_1  =  67.58 \ in^2

2

   A_2 =415.4 \ ft^2

3

   A_3  =  8.48 \ cm^2

4

  A_4 =  480.38 \ m^2

Step-by-step explanation:

Generally the area of a sector is mathematically represented as

         A =  \frac{\theta}{360} * \pi r^2

Now at r_1  = 11 in and  \theta_1 =  64^o

       A_1 =  \frac{64}{360} * 3.142  * 11^2

       A_1  =  67.58 \ in^2

Now at  r_2  = 20 ft in and  \theta_2  =  119 ^o

       A_2 =  \frac{119}{360} * 3.142 *  20^2

       A_2 =415.4 \ ft^2

Now at  r_3  = 6.5 cm   and  \theta_3 =  23 ^o

     A_3  =  \frac{23}{360} * 3.142 *  6.5 ^2

      A_3  =  8.48 \ cm^2

Now at  r_4  = 14.2 m   and  \theta_4 = 360 -87 =  273 ^o

         A_4 =  \frac{273}{360}  * 3.142 * 14.2^2

          A_4 =  480.38 \ m^2

6 0
3 years ago
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