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Alex73 [517]
3 years ago
11

Complete thse ordered pairs for this equation.

Mathematics
1 answer:
Lisa [10]3 years ago
7 0
(-2,2),(0,3),(2,4) 
if you plugg in the number it will give you the answer
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Please answer fast
Levart [38]

Answer:

Yes it is

Step-by-step explanation:

Because

2) x (sqrt 3) times (sqrt 12)

Two is also equivalent to sqrt of 4. The operation may be expressed as,

                                  (sqrt 4) x (sqrt 3) x sqrt (12)

The product is sqrt (144). This gives an answer of 12 and it is rational.

So, the answer is Yes!

Hope this helped! :)

May i have brainliest!

8 0
3 years ago
Which best describes the angles of some parallelograms? A. Four obtuse angles B. Four acute angles C. Two acute and two obtuse a
anyanavicka [17]
Some parallelograms have 2 obtuse and 2 acute angles.  

Parallelograms may have all 90 degree angles as well.  These are also called rectangles.  

When you "bend" a rectangle it naturally forms 2 acute and 2 obtuse angles.
5 0
3 years ago
What is the solution to the system of equations below?
Lelechka [254]

Answer:

D

Step-by-step explanation:

equation form: x=4, y=5

3 0
4 years ago
What is the error in this problem
castortr0y [4]

Answer:

12). LM = 37.1 units

13). c = 4.6 mi

Step-by-step explanation:

12). LM² = 23² + 20² - 2(23)(20)cos(119)°

    LM² = 529 + 400 - 920cos(119)°

    LM² = 929 - 920cos(119)°

    LM = \sqrt{929+446.03}

          = \sqrt{1375.03}

          = 37.08

          ≈ 37.1 units

13). c² = 5.4² + 3.6² - 2(5.4)(3.6)cos(58)°

    c² = 29.16 + 12.96 - 38.88cos(58)°

    c² = 42.12 - 38.88cos(58)°

    c = \sqrt{42.12-20.603}

    c = \sqrt{21.517}

    c = 4.6386

    c ≈ 4.6 mi

3 0
3 years ago
Ollie says, 'The probability of a football team winning is 1/3 because winning is only one out of the possible outcomes -win,los
Nezavi [6.7K]

Answer:

Kindly check explanation

Step-by-step explanation:

The possible outcome of football game is truly (Win lose or draw), hence, if the outcome only depends on just that one team, then the probability of winning is (required / total possible outcomes ; = 1/3). However, in football a game is played with an opposition team, of which there is a lot to consider in other to arrive at a winning probability, one is the relative strength of the teams, result of past meetings and so on. Hence, concluding that the probability of wining a football match is 1/3 based on the possible outcome (Win, lose or draw) is wrong.

4 0
3 years ago
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