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mihalych1998 [28]

3 years ago

11

A. Football is. Punted. Into. The air with. An upward velocity of 26ft/s. Its height h in feet after. T seconds is. Given. By th

e. Function h(t)=-16t^2+26t+3. What is. The. Football maximum height to. The nearest. Foot
Answers. Are 14ft b.15ft c.36ft or 194ft

1 answer:

Serga [27]3 years ago

8 0

Fivebjjvkkvfkcdhj sgh

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What is the remainder when x 3 - 7x - 6 is divided by the linear factor x - 4? 4

mart [117]

Hello,

P(x)=x^3-7x-6

P(4)=4^3-7*4-6=30
Remainder=30

6 0

3 years ago

Jana And Jordan had 23 oranges Jana had 7 fewer oranges than Jordan how many oranges did each girl have

Solnce55 [7]

Answer:

Jana had 8 oranges, and Jordan had 15 oranges.

Step-by-step explanation:

First, identify what you know:

1) In total, Jana and Jordan had 23 oranges.

2) Jana had 7 less oranges than Jordan.

We can create a formula, where x equals the number of oranges Jana has.

23 = x + (x + 7)

16 = x + x (subtracted 7 from both sides)

x = 8 (divided both sides by 2)

So, now we know Jana had 8 oranges, which is 7 less than Jordan.

8 + 7 = ?

? = 15

Jana had 8 oranges, while Jordan had 15, for a total of 23 oranges.

3 0

3 years ago

Simplify the expression (-8)^-3x15^0

avanturin [10]

The answer is -1 over 512 (fraction form)
ANSWER: -1/512

5 0

3 years ago

?????? help pls lolll

ki77a [65]

Answer is -9

Multiplying by 1/4 is the same as dividing by 4

-36(1/4) = -36/4 = -9

3 0

3 years ago

1. (a). A police car, approaching right-angled intersection from the north, is chasing a speedmg

tamaranim1 [39]

Answer:

<em>The SUV is running at 70 km/h</em>

Step-by-step explanation:

<u>Speed As Rate Of Change </u>

The speed can be understood as the rate of change of the distance in time. When the distance increases with time, the speed is positive and vice-versa. The instantaneous rate of change of the distance allows us to find the speed as a function of time.

This is the situation. A police car is 0.6 Km above the intersection and is approaching it at 60 km/h. Since the distance is decreasing, this speed is negative. On the other side, the SUV is 0.8 km east of intersection running from the police. The distance is increasing, so the speed should be positive. The distance traveled by the police car (y) and the distance traveled by the SUV (x) form a right triangle whose hypotenuse is the distance between them (d). We have:

$d=\sqrt{x^2+y^2}$

To find the instant speeds, we need to compute the derivative of d respect to the time (t). Since d,x, and y depend on time, we apply the chain rule as follows:

$\displaystyle d\ '=\frac{x.x'+y.y'}{\sqrt{x^2+y^2}}$

Where x' is the speed of the SUV and y' is the speed of the police car (y'=-60 km/h)

We'll compute :

$d=\sqrt{(0.8)^2+(0.6)^2}=\sqrt{0.64+0.36}$

$d=1\ km$

We know d'=20 km/h, so we can solve for x' and find the speed of the SUV

$\displaystyle \frac{x.x'+y.y'}{\sqrt{x^2+y^2}}=20$

Thus we have

$x.x'+y.y'=20$

Solving for x'

$\displaystyle x'=\frac{20-y.y'}{x}$

Since y'=-60

$\displaystyle x'=\frac{20+0.6(60)}{0.8}$

$x'=70\ km/h$

The SUV is running at 70 km/h

7 0

3 years ago