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pashok25 [27]
3 years ago
5

What operation does the Product Rule use

Mathematics
1 answer:
kumpel [21]3 years ago
4 0

Answer:

addition

Step-by-step explanation:

Example: 5^1 * 5^3= 5^4

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Linh has obtained scores of 82, 79, and 75 on her midterm algebra exams. If the final exam counts twice as much as a midterm, wh
OLga [1]

Answer:

She must make a score of 42 in the final exam to obtain an average of 80.

Step-by-step explanation:

Hi there!

Let x be the score of the final exam, the equation will be as follows (remember that the score of the final counts double):

(82 + 79 + 75 + 2x)/4 = 80

Let´s solve the equation for x multiplying each side of the equation be 4:

82 + 79 +75 + 2x = 320

Substract 82, 79 and 75 to both sides of the equation:

2x = 320 - 82 - 79 -75

2x = 84

x = 84/2

x = 42

She must make a score of 42 in the final exam to obtain an average of 80.

Have a nice day!

8 0
4 years ago
Match the function with the graph
Daniel [21]
The answer is B because it’s not a straight line and x can not have an exponent of 2 bc it will make it nonlinear
5 0
4 years ago
Need some help.
marishachu [46]

Answer:

1, 4, 5

Step-by-step explanation:

rational is when there is an end to the number.

6 0
3 years ago
A field is 53 1/3 yards wide. What is the width of the field in feet?
Umnica [9.8K]

Answer: The  width of the field = 160 feet

Step-by-step explanation:

We are given that , A field is 53\dfrac{1}{3} yards wide.

That means , The width of the field = 53\dfrac{1}{3} yards

Since , the fraction is in mixed for , so first we convert this into improper fraction.

53\dfrac{1}{3}=\dfrac{3(53)+1}{3}=\dfrac{160}{3}

Therefore , the width of the field = \dfrac{160}{3} yards

Since 1 yard = 3 feet.

⇒ the width of the field = \dfrac{160}{3}\times3 feet

Therefore , the width of the field = 160 feet

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3 years ago
67000000 in scientific notation
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Answer:

6.7 * 10^7

Step-by-step explanation:

7 0
4 years ago
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