The answer to this question is:
A circle is growing so that the radius is increasing at the rate of 2cm/min. How fast is the area of the circle changing at the instant the radius is 10cm? Include units in your answer.?
✔️I assume here the linear scale is changing at the rato of 5cm/min
✔️dR/dt=5(cm/min) (R - is the radius.... yrs, of the circle (not the side)
✔️The rate of area change would be d(pi*R^2)/dt=2pi*R*dR/dt.
✔️At the instant when R=20cm,this rate would be,
✔️2pi*20*5(cm^2/min)=200pi (cm^2/min) or, almost, 628 (cm^2/min)
Hoped This Helped, <span>Cello10
Your Welcome :) </span>
X is obviously 1
1x2=2
Entao...(So...)
Please mark as brainliest
T = 5 a
i = 4% aa
j = 1200
c = ...
j = cit/100
c = 100j / it
c = 100*1200 / 4*5
c = 120000 / 20
c = 12000/2
c = 6000
montante
M = c+j
M = 6000+1200
M = 7200
Answer:
A. 60°
Step-by-step explanation:
There's a very straight-forward explanation for this, thank god! XD
For this type of problem, there's a rule to follow for the outside angle. X and 120 should equal 180, so all you need to do is fill that gap.
180-120 = 60
60 is your answer because it completes the whole angle.
Step-by-step explanation:
4/sin45=
