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Nonamiya [84]
3 years ago
13

What is the answer to this?

Mathematics
2 answers:
Tanzania [10]3 years ago
8 0

Answer:

i think its 140 because u got to add all the sides in order to subtract from 180

i dont know  if its right but that is what i think UwU

Ket [755]3 years ago
4 0

Answer:

56

Step-by-step explanation:

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2.
Veronika [31]

Answer:

Hi, There! your Question was..- U.S. residents who are not citizens may not?

The Correct Answer is A. Serve on juries!

Hope this helps you! alot :P

Have a great day!

6 0
3 years ago
1. Mrs. Jones picks 3 flowers a day starting on Monday. How many does she have by Sunday?
Aleks04 [339]

Answer:

1. 18

2. 2412

Step-by-step explanation:

1. Monday 3

Tuesday 6

Wensday 9

Thursday 12

Friday 15

Sunday 18

_____________________________________________________

2.

603*4=2412

3 0
3 years ago
Select all the equations where y=10y=10y, equal, 10 is a solution.
vekshin1

Answer:

e. po sna makatulong pa heart nalang po salamat

4 0
3 years ago
Which of the following is equivalent to the midpoint between the points (8, -9) and (0, 5)?
olya-2409 [2.1K]
Add up the x points and divided by 2
same to go for the y points
so the and is (4,-2)

7 0
3 years ago
Assume that females have pulse rates that are normally distributed with a mean of μ=73.0 beats per minute and a standard deviati
Gennadij [26K]

Answer:

a. the probability that her pulse rate is less than 76 beats per minute is 0.5948

b. If 25 adult females are randomly​ selected,  the probability that they have pulse rates with a mean less than 76 beats per minute is 0.8849

c.   D. Since the original population has a normal​ distribution, the distribution of sample means is a normal distribution for any sample size.

Step-by-step explanation:

Given that:

Mean μ =73.0

Standard deviation σ =12.5

a. If 1 adult female is randomly​ selected, find the probability that her pulse rate is less than 76 beats per minute.

Let X represent the random variable that is normally distributed with a mean of 73.0 beats per minute and a standard deviation of 12.5 beats per minute.

Then : X \sim N ( μ = 73.0 , σ = 12.5)

The probability that her pulse rate is less than 76 beats per minute can be computed as:

P(X < 76) = P(\dfrac{X-\mu}{\sigma}< \dfrac{X-\mu}{\sigma})

P(X < 76) = P(\dfrac{76-\mu}{\sigma}< \dfrac{76-73}{12.5})

P(X < 76) = P(Z< \dfrac{3}{12.5})

P(X < 76) = P(Z< 0.24)

From the standard normal distribution tables,

P(X < 76) = 0.5948

Therefore , the probability that her pulse rate is less than 76 beats per minute is 0.5948

b.  If 25 adult females are randomly​ selected, find the probability that they have pulse rates with a mean less than 76 beats per minute.

now; we have a sample size n = 25

The probability can now be calculated as follows:

P(\overline X < 76) = P(\dfrac{\overline X-\mu}{\dfrac{\sigma}{\sqrt{n}}}< \dfrac{ \overline X-\mu}{\dfrac{\sigma}{\sqrt{n}}})

P( \overline X < 76) = P(\dfrac{76-\mu}{\dfrac{\sigma}{\sqrt{n}}}< \dfrac{76-73}{\dfrac{12.5}{\sqrt{25}}})

P( \overline X < 76) = P(Z< \dfrac{3}{\dfrac{12.5}{5}})

P( \overline X < 76) = P(Z< 1.2)

From the standard normal distribution tables,

P(\overline X < 76) = 0.8849

c. Why can the normal distribution be used in part​ (b), even though the sample size does not exceed​ 30?

In order to determine the probability in part (b);  the  normal distribution is perfect to be used here even when the sample size does not exceed 30.

Therefore option D is correct.

Since the original population has a normal distribution, the distribution of sample means is a normal distribution for any sample size.

5 0
3 years ago
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