Options A, C and D are functions.
In a function, for every number for 'x' there is only one 'y'. So, if you have two ordered pairs in a choice that have the same number for 'x', that is not a function.
Remember an ordered pair is written (x, y).
B is not a function as:
(x, y)
(1, -2)
(1, -3)
(1, -4)
^ All of the x-coordinates are the same.
E is not a function as:
(x, y)
(6, -1)
(6, -8)
^ Two of the x-coordinates are the same.
Thus, A, C and D are functions.
Responder:
500
Explicação passo a passo:
O número a subtrair de 12.750 em outro para obter 12.250
Deixe o número = x
Isso é ; se x for subtraído de 12750; nós obtemos 12250
12750 - x = 12.250
Subtraia 12750 de ambos os lados
12750 - x - 12750 = 12.250 - 12750
-x = - 500
x = 500
Answer:
(x+4)^2=-8(y+3)
Step-by-step explanation:
Given:
focus of parabola=(-4,-5)
directrix= -1
Standard form of parabola :
(x - h)^2 = 4p (y - k),
where focus is:
(h, k + p)
directrix is :
y = k - p
Now equating the values we get
(-4,-5) = (h,k+p)
h=-4
k+p=-5
k=-5-p
Also
y=-1 and y=k-p
i.e. k-p=-1
Substituting k=-5-p in above we get:
-5-p-p=-1
-2p=-1+5
p=4/-2
p=-2
Putting p=-2 in k-p=-1 we get:
k=-1-2
k=-3
Putting all the values in standard formula for parabola we get:
(x - (-4))^2 = 4(-2) (y -(-3))
(x+4)^2=-8(y+3)!
Answer:
The correct option is Histogram.
Step-by-step explanation:
In statistics, we usually come across a vast set of data. Data can be explained well when it is presented as a graph rather than as a table since the graphs have the capability to make known a trend or comparison.
Different types of graphs used in statistics to describe data are:
- Bar charts
- Pie charts
- Line charts
- Histogram
- Box Plot
- Dot Plot
And so on.
The methods commonly used for depicting a frequency distribution are:
- Histogram/Column graph
- Bar graph
- Frequency Polygon
- Pie chart
A histogram is used to graphically represent the distribution of a random variable according to the frequency distribution.
Each bar of the histogram is constructed according to a range of values and represents the frequency for that particular range.
In this case, we need to find how many pumpkins had masses below 6.0 kilograms.
The histogram can be used to construct the graphically representation of the masses of pumpkins and their frequency.
The range can be decided according to the provided masses.
Thus, the correct option is Histogram.
Step-by-step explanation:
let the point be (h,k)
for a given line, ax+by+c
d=∣∣∣ah+bk+ca2+b2−−−−−−√∣∣∣
so, 2≤d1p+d2p≤4
2≤∣∣∣h−k2–√∣∣∣+∣∣∣h+k2–√∣∣∣≤4
22–√≤|h−k|+|h+k|
ifh>k
22–√≤h−k+h+k≤42–√
2–√≤h≤22–√
ifh<k
22–√≤−h+k+h+k≤42–√
2–√≤k≤22–√
area of shaded region
area = (22–√)2−2–√2
=6unit2
