Answer:
6 different primes.
3, 7, 13, 29, 31 , 89.
Step-by-step explanation:
Try dividing by primes starting with 3:
3 ) 65529009
3 ) 21843003
7) 7281001
13) 1040143
29) 80011
31 ( 2759
89. 89 is a prime number.
Multiply the numerator and denominator by 7×2 = 14 to eliminate the denominators of those fractions:
Rationalize the denominator by multiplying both numerator and denominator by √10:
Lastly, cancel the common factor of 2 in both the numerator and denominator (which comes from 6 = 2×3 and 490 = 2×245):
Answer: x = (sqrt(7) + 2)/3 and
x = ( – sqrt(7) + 2)/3
Explanation:
3x^2 - 4x - 1 = 0
Divide both sides by 3:
3x^2/3 - 4/3x - 1/3 = 0/3
x^2 - 4/3x - 1/3 = 0
x^2 - 4/3x = 1/3
x^2 - 4/3x + (2/3)^2 = 1/3 + (2/3)^2
(x - 2/3)^2 = 1/3 + 4/9
(x - 2/3)^2 = 7/9
Sqrt both sides:
x - 2/3 = sqrt (7/9)
x - 2/3 = |sqrt(7)/3|
Set x -2/3 = sqrt(7)/3
=> x = (sqrt(7) + 2)/3
Set x - 2/3 = - sqrt(7)/3
=> x = ( - sqrt(7) + 2)/3
72 divided by 9 = 8
8 + 4x4 = 8+16
8+16=24
