14:6=28:18 42:7=6:2 2:3=3:2 3:5=12:20
1 answer:
You might be interested in
Answer:
Step-by-step explanation:
Given : Jennifer got a box of chocolates. the box is a right triangular prism shaped box. it is 7 in long. and the triangular base measure 2in times 3in times 4in.
a = 2
b=3
c=4
To Find : what is the surface area of the box of chocolates?
Solution: The first thing we should know is the area of the triangular base.
Triangular base area:
Where, s is the semi-meter of the triangle:
a, b, c: sides of the triangle.
Substituting:
s = (2 + 3 + 4) /2=4.5
A1 = 2.90
Then, you must know the area of each rectangle associated with each side of the triangular base.
Rectangle area 1: Ar1 = (a) * (l)
Ar1 = (2) * (7)
Ar1 = 14
Rectangular area 2: Ar2 = (b) * (l)
Ar2 = (3) * (7)
Ar2 = 21
Rectangular area 3: Ar3 = (a) * (l)
Ar3 = (4) * (7)
Ar3 = 28
Finally the surface area is: A = Ar1 + Ar2 + Ar3 + 2 * A1
A = (14) + (21) + (28) + 2 * (2.90)
Hence the surface area of the box of chocolates is