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mariarad [96]
3 years ago
9

The numbers 4, 5, 6, and 7 are on a spinner. You spin the spinner twice. Which calculation proves that landing on an even number

for the first spin and the second spin are independent events?
Mathematics
2 answers:
Svetach [21]3 years ago
7 0

Answer:

We can determine this by looking at the odds of getting an even number on the second spin given an even first spin and an odd first spin. If you look at both situations, there is still a 50% chance of getting an even number on the second spin. Given this fact, we can tell that the first spin doesn't affect it and therefore they are independent events.

drek231 [11]3 years ago
3 0

Answer:

C

Step-by-step explanation:


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How to solve for y.
NARA [144]
25, 65, and y make a right triangle. use a^2 + b^2 =c^2. 
so...
y^2 + 25^2 = 65^2
y^2 + 625 = 4225 
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7 0
3 years ago
Expand the given power by using Pascal’s triangle. (9a - 10b)^6
xxMikexx [17]

Answer:

531441a^6-3542940a^5b+9841500a^4b^2-14580000a^3b^3+12150000a^2b^4-5400000ab^5+1000000b^6

Step-by-step explanation:

                     1                                n=0

                  1      1                            n=1

                 1   2   1                           n=2

                1  3  3  1                          n=3

              1  4  6  4   1                      n=4

             1  5 10 10 5  1                    n=5

           1 6 15 20 15 6 1                   n=6

This is where n is the exponent in

(x+y)^n.

(x+y)^6=1x^6+6x^5y+15x^4y^2+20x^3y^3+15x^2y^4+6xy^5+1y^6

Now we want to expand:

(9a-10b)^6 or we we can rewrite as (9a+(-10b))^6.

Let's replace x with (9a) and y with (-10b) in the expansion:

(x+y)^6=1x^6+6x^5y+15x^4y^2+20x^3y^3+15x^2y^4+6xy^5+1y^6

((9a)+(-10b))^6

=1(9a)^6+6(9a)^5(-10b)+15(9a)^4(-10b)^2+20(9a)^3(-10b)^3+15(9a)^2(-10b)^4+6(9a)(-10b)^5+1(-10b)^6

Let's simplify a bit:

=9^6a^6-60(9)^5a^5b+15(-10)^2(9)^4a^4b^2+20(9)^3(-10)^3a^3b^3+15(9)^2(-10)^4a^2b^4+6(9)(-10)^5ab^5+(-10)^6b^6

=531441a^6-3542940a^5b+9841500a^4b^2-14580000a^3b^3+12150000a^2b^4-5400000ab^5+1000000b^6

8 0
3 years ago
F(t) = t-1<br> g(t)= t^3 + 4t<br> Find (f -g)(t)
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Answer:

Step-by-step explanation:

t - 1 - t^3 - 4t

-t^3 - 3t

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Use the picture provided to figure out the combination.
AlladinOne [14]

Answer:

4223?

Step-by-step explanation:

i need morw context

4 0
2 years ago
What can you multiply by 1050 to get 21,000? <br><br> Proportional Problem!
FinnZ [79.3K]

Answer:

If you multiple 1050 by 20 you will get 21,000.

5 0
3 years ago
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