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mariarad [96]
3 years ago
9

The numbers 4, 5, 6, and 7 are on a spinner. You spin the spinner twice. Which calculation proves that landing on an even number

for the first spin and the second spin are independent events?
Mathematics
2 answers:
Svetach [21]3 years ago
7 0

Answer:

We can determine this by looking at the odds of getting an even number on the second spin given an even first spin and an odd first spin. If you look at both situations, there is still a 50% chance of getting an even number on the second spin. Given this fact, we can tell that the first spin doesn't affect it and therefore they are independent events.

drek231 [11]3 years ago
3 0

Answer:

C

Step-by-step explanation:


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please help me, Prove a quadrilateral with vertices G(1,-1), H(5,1), I(4,3) and J(0,1) is a rectangle using the parallelogram me
mestny [16]

Answer:

Step-by-step explanation:

We are given the coordinates of a quadrilateral that is G(1,-1), H(5,1), I(4,3) and J(0,1).

Now, before proving that this quadrilateral is a rectangle, we will prove that it is a parallelogram. For this, we will prove that the mid points of the diagonals of the quadrilateral are  equal, thus

Join JH and GI such that they form the diagonals of the quadrilateral.Now,

JH=\sqrt{(5-0)^{2}+(1-1)^{2}}=5 and

GI=\sqrt{(4-1)^{2}+(3+1)^{2}}=5

Now, mid point of JH=(\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})

=(\frac{5+0}{2},\frac{1+1}{2})=(\frac{5}{2},1)

Mid point of GI=(\frac{5}{2},1)

Since, mid point point of JH and GI are equal, thus GHIJ is a parallelogram.

Now, to prove that it is a rectangle, it is sufficient to prove that it has a right angle by using the Pythagoras theorem.

Thus, From ΔGIJ, we have

(GI)^{2}=(IJ)^{2}+(JG)^{2}                             (1)

Now, JI=\sqrt{(4-0)^{2}+(3-1)^{2}}=\sqrt{20} and GJ=\sqrt{(0-1)^{2}+(1+1)^{2}}=\sqrt{5}

Substituting these values in (1), we get

5^{2}=(\sqrt{20})^{2}+(\sqrt{5})^{2} }

25=20+5

25=25

Thus, GIJ is a right angles triangle.

Hence, GHIJ is a rectangle.

Also, The diagonals GI=\sqrt{(4-1)^{2}+(3+1)^{2}}=5  and HJ=\sqrt{(0-5)^2+(1-1)^2}=5 are equal, thus, GHIJ is a rectangle.

6 0
3 years ago
PLEASE HELP!!!! :((
olga_2 [115]
C is the answer.
The other ones do not make as much sense i am not completely sure.
8 0
3 years ago
1. Calculate the area of the circle having the following radius (r) or diameter (d) (π= 3.14) (a) Radius (r) = 3 cm (b) Diameter
Marat540 [252]

The area of circle having radius 3cm is 28.27 cm², diameter 5cm is 19.63 cm², radius 8 ft is 201.06 ft², diameter is 113.1 cm², diameter 20 km is 314.16 km², diameter 15 mm is 176.71 mm² and radius 16 yd is 804.25 yd².

Given the radius and diamtere are (a) Radius (r) = 3 cm (b) Diameter (d) = 5 cm (c) Radius (r) = 8 ft. (d) Diameter (d) = 12 cm (f) Diameter (d) = 20 km (g) Diameter (d) = 15 mm (i) Radius (r) = 16 yd​.

We will calculate the area of circle by using the formula A=πr² or π(d/2)².

(a) Radius (r)=3cm

The area of circle is

Area=π(3)²

Area =9π

Here, π=3.14, we get

Area =9×3.14

Area=28.27cm²

(b) Diameter (d)=5cm

The area of circle is

Area=π(5/2)²

Area =π(2.5)²

Area=6.25π

Here, π=3.14, we get

Area =6.25×3.14

Area=19.63cm²

(c) Radius (r)=8 ft

The area of circle is

Area=π(8)²

Area =64π

Here, π=3.14, we get

Area =64×3.14

Area=201.06ft²

(d) Diameter (d)=12cm

The area of circle is

Area=π(12/2)²

Area =36π

Here, π=3.14, we get

Area =36×3.14

Area=113.1cm²

(e) Diameter (d)=20km

The area of circle is

Area=π(20/2)²

Area =100π

Here, π=3.14, we get

Area =100×3.14

Area=314.16km²

(f) Diameter (d)=15mm

The area of circle is

Area=π(15/2)²

Area =56.25π

Here, π=3.14, we get

Area =56.25×3.14

Area=176.71mm²

(g) Radius (r)=16yd

The area of circle is

Area=π(16)²

Area =256π

Here, π=3.14, we get

Area =256×3.14

Area=804.25yd²

Hence, the area of circle having radius and diameter is  radius 3cm is 28.27 cm², diameter 5cm is 19.63 cm², radius 8 ft is 201.06 ft², diameter is 113.1 cm², diameter 20 km is 314.16 km², diameter 15 mm is 176.71 mm² and radius 16 yd is 804.25 yd².

Learn more about the area of circle from here brainly.com/question/17096708

#SPJ9

3 0
1 year ago
5-x=3 <br> Work out the value of 3x^2
Oxana [17]

Answer:

12

Step-by-step explanation:

5 - x = 3 \\  \\ 5  - 3 = x \\  \\ 2 = x \\  \\ x = 2 \\  \\ 3 {x}^{2}  = 3 {(2)}^{2}  = 3 \times 4 = 12

8 0
3 years ago
Need help with z-scores
zysi [14]

hope this helps b.0.8937

6 0
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